3 + 3 = ?
4 + 5 = ?
6 + 6 = ?
2 + 3 = ?
Visual: π‘π‘ + π‘π‘ = π‘π‘π‘π‘ (doubles) | π΅π΅π΅ + π΅π΅π΅π΅ = π΅π΅π΅π΅π΅π΅π΅ (near doubles)
Doubles: Addition facts where both addends are identical numbers (e.g., 3+3, 6+6)
Near Doubles: Addition facts where addends are consecutive numbers (e.g., 4+5, 2+3)
- Look at both numbers: Are they the same? β Doubles
- If different: Are they consecutive (one apart)? β Near Doubles
- Count the difference: Same numbers = 0 difference (doubles), 1 difference (near doubles)
- Apply the appropriate strategy: Doubles rule or near doubles rule
Both numbers are 3, so this is a doubles fact: 3 + 3
When both numbers are the same: 3 + 3 = 6 (3 Γ 2 = 6)
4 + 5: Different numbers, but consecutive (4 and 5 differ by 1) β Near Doubles
6 + 6: Both same β Doubles | 2 + 3: Consecutive β Near Doubles
4 + 5 = Near Doubles
6 + 6 = Doubles
2 + 3 = Near Doubles
Doubles: 3+3, 6+6 | Near Doubles: 4+5, 2+3
β’ Identification Rule: Same numbers = Doubles, consecutive numbers = Near Doubles
β’ Decision-Making: Distinguish between problem types before calculating
β’ Pattern Recognition: Identifying the relationship between addends
5 + 6 = ? (Type: Near Doubles)
7 + 7 = ? (Type: Doubles)
8 + 9 = ? (Type: Near Doubles)
4 + 4 = ? (Type: Doubles)
Visual: π΄π΄π΄π΄ + π΄π΄π΄π΄ = π΄π΄π΄π΄π΄π΄π΄π΄ (doubles) | π’π’π’π’π’ + π’π’π’π’π’π’ = π’π’π’π’π’π’π’π’π’ (near doubles)
Decision Making: The process of identifying whether an addition problem is a doubles or near doubles fact before solving
5 and 6 are consecutive numbers (one apart), so this is a near doubles fact
Think of 5 + 5 = 10, then add 1 more: 10 + 1 = 11
7 + 7: Both numbers are the same β Doubles
7 + 7 = 14 (7 Γ 2 = 14)
Continue identifying type then applying appropriate strategy
7 + 7 = 14 (Doubles)
8 + 9 = 17 (Near Doubles)
4 + 4 = 8 (Doubles)
5+6=11 (ND), 7+7=14 (D), 8+9=17 (ND), 4+4=8 (D)
β’ Type Identification: Determine problem type before solving
β’ Strategy Selection: Use appropriate method for each type
β’ Sequential Processing: Apply consistent steps to each problem
1 + 1, 3 + 4, 5 + 5, 6 + 7, 8 + 8, 9 + 10, 2 + 2
Visual: π + π = π π (doubles) | π£π£ + π£π£π£ = π£π£π£π£π£ (near doubles)
Advanced Identification: Distinguishing between doubles and near doubles in mixed sets of problems
1+1: Same numbers β Doubles | 3+4: Consecutive β Near Doubles
5+5: Same β Doubles | 6+7: Consecutive β Near Doubles
8+8: Same β Doubles | 9+10: Consecutive β Near Doubles | 2+2: Same β Doubles
Separate doubles from near doubles for clarity
Double-check each classification to ensure accuracy
Near Doubles: 3+4, 6+7, 9+10
Doubles: 1+1, 5+5, 8+8, 2+2 | Near Doubles: 3+4, 6+7, 9+10
β’ Systematic Analysis: Examine each problem individually
β’ Classification: Group problems by type for better organization
β’ Verification: Check classifications for accuracy
Doubles: Addition of identical numbers (e.g., 3+3, 8+8)
Near Doubles: Addition of consecutive numbers (e.g., 4+5, 7+8)
Decision Making: The process of identifying which strategy to use
- Examine both addends: Look at the two numbers being added
- Compare the numbers: Are they identical or different?
- Determine the difference: 0 difference = Doubles, 1 difference = Near Doubles
- Select strategy: Use appropriate method based on type
- Calculate: Apply the chosen strategy
β’ Same numbers = Doubles (2+2, 5+5, 8+8)
β’ Consecutive numbers = Near Doubles (3+4, 6+7, 9+10)
β’ Non-consecutive different numbers = Neither (2+5, 3+8)
1. Look at both numbers
2. Are they the same?
3. If yes β Doubles
4. If no, are they consecutive?
5. If yes β Near Doubles
Doubles: Equal groups side by side
Near Doubles: One group has one more
Improves calculation speed
Reduces errors
Builds number sense