Correlation coefficient: A statistical measure that calculates the strength of the relationship between the relative movements of two variables.
Linear regression: A statistical method that allows us to summarize and study relationships between two continuous variables.
Slope: The steepness of the regression line, representing the change in y for each unit change in x.
- Extract data pairs (study hours, test scores) for each grade
- Calculate correlation coefficient for each grade
- Perform linear regression analysis for Grade 7
- Interpret the regression parameters
- Make predictions using the regression equation
Assuming: 1-2hrs = 1.5, 2-3hrs = 2.5, 3-4hrs = 3.5, 4-5hrs = 4.5
Grade 6: (1.5, 75), (2.5, 85), (3.5, 90), (4.5, 70)
Grade 7: (1.5, 70), (2.5, 80), (3.5, 88), (4.5, 65)
Grade 8: (1.5, 60), (2.5, 72), (3.5, 82), (4.5, 55)
Grade 9: (1.5, 50), (2.5, 65), (3.5, 75), (4.5, 45)
Using the formula r = [n(Σxy) - (Σx)(Σy)] / √[nΣx² - (Σx)²][nΣy² - (Σy)²]
Grade 6: r ≈ 0.25 (weak positive)
Grade 7: r ≈ 0.16 (very weak positive)
Grade 8: r ≈ 0.19 (very weak positive)
Grade 9: r ≈ 0.15 (very weak positive)
Note: The correlation is unexpectedly weak in all grades, possibly due to limited data points.
For Grade 7: x̄ = 3, ȳ = 75.75
Numerator: Σ(xi-x̄)(yi-ȳ) = (1.5-3)(70-75.75) + (2.5-3)(80-75.75) + (3.5-3)(88-75.75) + (4.5-3)(65-75.75)
= (-1.5)(-5.75) + (-0.5)(4.25) + (0.5)(12.25) + (1.5)(-10.75)
= 8.625 - 2.125 + 6.125 - 16.125 = -3.5
Denominator: Σ(xi-x̄)² = (-1.5)² + (-0.5)² + (0.5)² + (1.5)² = 2.25 + 0.25 + 0.25 + 2.25 = 5
Slope (m) = -3.5 ÷ 5 = -0.7
Y-intercept (b) = ȳ - mx̄ = 75.75 - (-0.7)(3) = 75.75 + 2.1 = 77.85
Regression equation: y = -0.7x + 77.85
y = -0.7(6) + 77.85 = -4.2 + 77.85 = 73.65
A student studying 6 hours would be predicted to score 73.65
Strongest correlation: Grade 6 (r ≈ 0.25). Regression equation: y = -0.7x + 77.85. Predicted score for 6 hours: 73.65.
• Correlation coefficient: r ranges from -1 to 1, where values closer to ±1 indicate stronger relationships
• Linear regression: y = mx + b, where m is slope and b is y-intercept
• Regression interpretation: Slope indicates direction and strength of relationship
Conditional probability: The probability of an event occurring given that another event has already occurred.
Joint probability: The probability of two events occurring together.
Proportional allocation: Distributing resources based on the proportion of each category.
Students participating in both = 150
Total students = 720
Fraction = 150/720 = 5/24
P(Sports | Arts) = P(Sports AND Arts) ÷ P(Arts)
Students in Arts = Arts Only + Both = 210 + 150 = 360
P(Sports | Arts) = 150 ÷ 360 = 5/12
Students in Sports = Sports Only + Both = 180 + 150 = 330
P(Arts | Sports) = 150 ÷ 330 = 5/11
Sports: (180+150)/720 = 330/720 = 11/24
Arts: (210+150)/720 = 360/720 = 1/2
Both: 150/720 = 5/24
Sports budget: (11/24) × $36,000 = $16,500
Arts budget: (1/2) × $36,000 = $18,000
Both budget: (5/24) × $36,000 = $7,500
Fraction: 5/24. P(Sports|Arts): 5/12. P(Arts|Sports): 5/11. Budgets: Sports $16,500, Arts $18,000, Both $7,500.
• Conditional probability: P(A|B) = P(A and B) ÷ P(B)
• Proportional allocation: (Part ÷ Whole) × Total Amount
• Joint probability: P(A and B) = P(A) × P(B|A)
Normal distribution: A continuous probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
Z-score: A numerical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean.
Variance: The average of the squared differences from the mean.
Using midpoints: 54.5, 64.5, 74.5, 84.5, 94.5, 100
Mean = [(54.5×2) + (64.5×4) + (74.5×8) + (84.5×12) + (94.5×10) + (100×4)] ÷ 40
= [109 + 258 + 596 + 1014 + 945 + 400] ÷ 40
= 3322 ÷ 40 = 83.05
With 40 students, median is average of 20th and 21st values when ordered.
First 2 scores: 50-59, next 4: 60-69, next 8: 70-79 (total 14), next 12: 80-89 (total 26)
Both 20th and 21st values fall in the 80-89 range. We'll approximate the median as 84.5.
Mode = 80-89 range (most frequent, with 12 students)
Range = 100 - 50 = 50
Variance = Σ(fi × (mi - x̄)²) ÷ n
Where fi is frequency and mi is midpoint
= [2×(54.5-83.05)² + 4×(64.5-83.05)² + 8×(74.5-83.05)² + 12×(84.5-83.05)² + 10×(94.5-83.05)² + 4×(100-83.05)²] ÷ 40
= [2×817.20 + 4×344.10 + 8×73.10 + 12×2.10 + 10×131.10 + 4×287.30] ÷ 40
= [1634.4 + 1376.4 + 584.8 + 25.2 + 1311 + 1149.2] ÷ 40
= 6081 ÷ 40 = 152.03
Standard deviation = √152.03 ≈ 12.33
Lowest score (54.5): z = (54.5 - 83.05) ÷ 12.33 ≈ -2.32
Highest score (100): z = (100 - 83.05) ÷ 12.33 ≈ 1.38
Students scoring 70-90: 8 (70-79) + 12 (80-89) + 5 (90-99) = 25 students
Percentage = (25 ÷ 40) × 100 = 62.5%
For a normal distribution, scores between 70 and 90 correspond to z-scores between (70-83.05)÷12.33 ≈ -1.06 and (90-83.05)÷12.33 ≈ 0.57
Using standard normal table: P(-1.06 < Z < 0.57) ≈ 0.7157 - 0.1446 = 0.5711 or 57.11%
Mean: 83.05. Median: ~84.5. Mode: 80-89. Range: 50. Variance: ~152.03. Std dev: ~12.33. Z-scores: -2.32, 1.38. Actual % 70-90: 62.5%. Expected % if normal: 57.11%.
• Grouped data mean: Σ(fi × mi) ÷ n
• Variance formula: Σ(fi × (mi - x̄)²) ÷ n
• Z-score formula: z = (x - μ) ÷ σ
• Normal distribution: Approximately 68% within 1 SD, 95% within 2 SD
Department A (3% growth): Starts at $50K, grows exponentially
After 12 months: $50K × (1.03)^12 ≈ $71.3K
Annual total: Sum of geometric series = $50K × [(1.03)^12 - 1] ÷ 0.03 ≈ $703.2K
Department B (linear growth): $45K, $46.5K, ..., $63K
Annual total: $45K × 12 + $1.5K × (1+2+...+11) = $540K + $1.5K × 66 = $639K
Department C (2% decline): $60K × [(1-0.02)^12 - 1] ÷ (-0.02) ≈ $646.8K
Department D (constant): $55K × 12 = $660K
Department E (1.5% growth): $40K × [(1.015)^12 - 1] ÷ 0.015 ≈ $518.4K
Total = $703.2K + $639K + $646.8K + $660K + $518.4K = $3,167.4K
End of year: A: $71.3K, B: $63K, C: $47.1K, D: $55K, E: $47.8K
Department A has the highest revenue at the end of the year ($71.3K)
Department A's annual revenue: $703.2K
Percentage = ($703.2K ÷ $3,167.4K) × 100 ≈ 22.2%
CAGR = (Ending Value ÷ Beginning Value)^(1/n) - 1
Where n = number of years = 1
CAGR = ($71.3K ÷ $50K)^(1/1) - 1 = 1.426 - 1 = 0.426 or 42.6%
Total annual revenue: $3,167,400. Highest dept at year end: A ($71.3K). A's %: ~22.2%. CAGR for A: 42.6%.
• Compound growth: Final value = Initial value × (1 + growth rate)^n
• Geometric series: Sum = a × (r^n - 1) ÷ (r - 1) for growth rate r
• CAGR formula: (End Value ÷ Beginning Value)^(1/n) - 1
• Linear growth: Add a constant amount each period
Chi-square test: A statistical test used to determine if there is a significant difference between observed and expected frequencies.
Null hypothesis: A statement that there is no significant difference between observed and expected values.
Confidence interval: A range of values that is likely to contain the true population parameter.
Goodness of fit: A statistical test that determines whether sample data matches a population distribution.
| Category | Observed (O) | Expected (E) | (O-E)² | (O-E)²/E |
|---|---|---|---|---|
| Category A | 10 | 20 | (10-20)² = 100 | 100/20 = 5 |
| Category B | 20 | 20 | (20-20)² = 0 | 0/20 = 0 |
| Category C | 30 | 20 | (30-20)² = 100 | 100/20 = 5 |
| Category D | 15 | 20 | (15-20)² = 25 | 25/20 = 1.25 |
| Category E | 25 | 20 | (25-20)² = 25 | 25/20 = 1.25 |
χ² = Σ(Observed - Expected)²/Expected
χ² = 5 + 0 + 5 + 1.25 + 1.25 = 12.5
df = number of categories - 1 = 5 - 1 = 4
For α = 0.05, critical χ² value with df = 4 is approximately 9.488
Since our calculated χ² (12.5) > critical value (9.488), we reject the null hypothesis
This means the observed distribution significantly differs from the expected uniform distribution.
Assuming these are scores: A=1, B=2, C=3, D=4, E=5
Mean = (1×10 + 2×20 + 3×30 + 4×15 + 5×25) ÷ 100 = (10+40+90+60+125) ÷ 100 = 325 ÷ 100 = 3.25
Standard deviation ≈ 1.37
For 95% CI: Mean ± 1.96×(SD/√n) = 3.25 ± 1.96×(1.37/√100) = 3.25 ± 0.27
CI = [2.98, 3.52]
Chi-square: 12.5. Critical value: 9.488. Reject null hypothesis. CI: [2.98, 3.52].
• Chi-square formula: χ² = Σ(O-E)²/E
• Degrees of freedom: df = k-1 (k = number of categories)
• Hypothesis testing: Reject null if test statistic > critical value
• Confidence interval: Mean ± z×(SD/√n)
Weeks 1-7 show increasing trend (100, 115, 130, 145, 160, 175, 190)
Weeks 8-10 show decreasing trend (180, 170, 160)
The pattern shows an increase followed by a decrease, possibly cyclical.
Week 11 forecast = (190 + 180 + 170) ÷ 3 = 180
Week 12 forecast = (180 + 170 + 160) ÷ 3 = 170
Continuing this pattern, Week 15 forecast ≈ 130, Week 16 forecast ≈ 120
Initial forecast F₁ = A₁ = 100
F₂ = αA₁ + (1-α)F₁ = 0.3(100) + 0.7(100) = 100
F₃ = 0.3(115) + 0.7(100) = 104.5
Continuing: F₄=112.15, F₅=121.0, F₆=132.7, F₇=145.4, F₈=155.8, F₉=160.1, F₁₀=160.1
Week 15 forecast ≈ 145, Week 16 forecast ≈ 145
For simplicity, let's calculate MAE for weeks 4-10:
Moving average (3-week): Forecasts: 125, 130, 145, 160, 170, 175, 180
Actual: 145, 160, 175, 180, 170, 160, 150 (assuming Week 11-13 continue the pattern)
Errors: 20, 30, 30, 20, 0, 15, 30
MAE = (20+30+30+20+0+15+30) ÷ 7 ≈ 20.7
For exponential smoothing: Errors are generally smaller due to the smoothing effect.
Assuming exponential smoothing forecast of 145 with standard error of 10
95% CI = 145 ± 1.96×10 = [125.4, 164.6]
MA forecast: W15=130, W16=120. ES forecast: W15=W16=145. CI for W15: [125.4, 164.6]. ES is more accurate.
• Moving average: Fₜ₊₁ = (Aₜ + Aₜ₋₁ + ... + Aₜ₋ₙ₊₁) ÷ n
• Exponential smoothing: Fₜ₊₁ = αAₜ + (1-α)Fₜ
• MAE: Mean Absolute Error = Σ|Aₜ - Fₜ| ÷ n
• Confidence interval: Forecast ± z×SE
Hypergeometric distribution: A discrete probability distribution that describes the probability of k successes in n draws, without replacement, from a finite population of size N that contains exactly K successes.
Expected value: The weighted average of all possible outcomes in a probability distribution.
Binomial distribution: The probability distribution of the number of successes in a sequence of n independent experiments.
Ratio is 7:5, so for every 7+5=12 parts, 7 are experienced and 5 are novice
Total members = 120
Each part = 120 ÷ 12 = 10
Experienced competitors = 7 × 10 = 70
Novice competitors = 5 × 10 = 50
This follows hypergeometric distribution:
P(all 3 experienced) = C(70,3) × C(50,0) ÷ C(120,3)
= [70!/(3!×67!)] × [50!/(0!×50!)] ÷ [120!/(3!×117!)]
= (70×69×68/6) × 1 ÷ (120×119×118/6)
= 54,740 ÷ 280,840 ≈ 0.195 or 19.5%
Maintaining 7:5 ratio with 96 total members:
Total parts = 7 + 5 = 12
Each part = 96 ÷ 12 = 8
Experienced = 7 × 8 = 56
Novice = 5 × 8 = 40
This follows hypergeometric distribution with N=120, K=70, n=5
Expected value = n × (K/N) = 5 × (70/120) = 5 × 0.583 = 2.92
Variance = n × (K/N) × ((N-K)/N) × ((N-n)/(N-1))
= 5 × (70/120) × (50/120) × (115/119)
= 5 × 0.583 × 0.417 × 0.966 ≈ 1.16
Math Olympiad: 70 exp, 50 nov. Prob all 3 exp: ~19.5%. New club: 56 exp, 40 nov. Sample of 5: E(X)=2.92, Var=1.16.
• Hypergeometric probability: P(X=k) = C(K,k) × C(N-K,n-k) ÷ C(N,n)
• Expected value: E(X) = n × (K/N)
• Variance: Var(X) = n × (K/N) × ((N-K)/N) × ((N-n)/(N-1))
• Ratio maintenance: Keep the same proportion when scaling
Bar graph: A chart with bars showing data visually
X-axis: The horizontal line showing categories
Y-axis: The vertical line showing numbers
Data: Information shown in the graph
Scale: The numbers on the y-axis that show the values
Range: The difference between the highest and lowest values
Mode: The value that appears most frequently
Median: The middle value when data is ordered
Mean: The average of all values
Frequency: How often something occurs
Cumulative frequency: Running total of frequencies
Ratio: Comparison of two quantities
Probability: Likelihood of an event occurring
Standard deviation: Measure of data spread from the mean
Correlation: Relationship between variables
Variance: Average of squared differences from the mean
Outlier: Data point significantly different from others
IQR: Interquartile range (Q3-Q1)
Z-score: Standardized score indicating distance from mean
Regression: Statistical method for modeling relationships
Chi-square: Statistical test for categorical data
Hypothesis testing: Statistical method to evaluate claims
Confidence interval: Range likely to contain true parameter
- Look at the title: Understand what the graph shows
- Read categories: See what each bar represents
- Check the scale: See what numbers the y-axis shows
- Compare bars: Look at heights to see differences
- Calculate differences: Subtract values to find how many more/less
- Perform statistical analysis: Calculate averages, ranges, etc.
- Make predictions: Look for patterns in the data
- Apply mathematical concepts: Use ratios, probabilities, etc.
- Identify trends: Recognize correlations and patterns
- Test hypotheses: Evaluate statistical claims
• Tallest bar = Most: Highest bar shows the largest number
• Shortest bar = Least: Lowest bar shows the smallest number
• Compare by subtracting: To find difference, subtract smaller from larger
• Total = Add all: To find total, add all values together
• Read carefully: Always check the title and labels
• Accurate scaling: Each unit on y-axis must represent the same value
• Average = Sum ÷ Count: Total of values divided by number of values
• Range = Max - Min: Difference between highest and lowest values
• Percentage = (Part ÷ Whole) × 100: Convert fractions to percentages
• Probability = Favorable ÷ Total: Likelihood of an event
• Ratio proportion: If a:b = c:d, then a/b = c/d
• Standard deviation: σ = √[Σ(xi - μ)²/N]
• Variance: σ² = Σ(xi - μ)²/N
• Correlation coefficient: r = [Σ(xi-x̄)(yi-ȳ)]/[√Σ(xi-x̄)² × √Σ(yi-ȳ)²]
• Regression line: y = mx + b where m is slope and b is y-intercept
• Chi-square test: χ² = Σ(Observed - Expected)²/Expected
A bar graph uses bars to show information.
It helps us see which group has more or less.
The bars can be vertical (up and down) or horizontal (side to side).
Bar graphs make it easy to compare different amounts.
They're useful for statistical analysis and data interpretation.
Can show single or multiple data sets.
Used for categorical data comparisons.
Title: Tells us what the graph is about
X-axis: Bottom line showing categories (like colors, animals, etc.)
Y-axis: Side line showing numbers
Bars: Show the amount for each category
Scale: Numbers on the y-axis that show values
Legend: Explains what different colors represent
Grid lines: Help read values more accurately
Data labels: Show exact values on bars
Most = Tallest bar
Least = Shortest bar
Difference = Subtract smaller from larger
Total = Add all values together
Average = Sum ÷ Number of values
Range = Highest - Lowest value
Mode = Most frequent value
Median = Middle value when ordered
Percentage = (Part ÷ Whole) × 100
Ratio = Comparison of two quantities
Probability = Favorable ÷ Total outcomes
Standard Deviation = Data spread measure
Variance = Squared spread measure
Correlation = Relationship strength
Regression = Predictive relationship
Chi-square = Goodness of fit test
Not reading the title: Always check what the graph is about before answering questions.
Counting incorrectly: Count the exact height of each bar carefully.
Confusing most and least: Remember: tallest bar = most, shortest bar = least.
Wrong operation: To find "how many more", subtract (not add).
Ignoring the scale: Always check what numbers the y-axis represents.
Miscalculating averages: Remember to divide the sum by the number of values.
Error in median calculation: Always order data before finding the median.
Incorrect percentage: Divide the part by the whole, not the other way around.
Probability confusion: Favorable outcomes ÷ Total outcomes.
Standard deviation error: Remember to square deviations and take the square root.
Correlation misinterpretation: Correlation does not imply causation.
Outlier oversight: Identify and consider outliers when analyzing data.
Hypothesis testing error: Properly define null and alternative hypotheses.
Confidence interval mistake: Use appropriate critical value for confidence level.