Show with flats, rods, and units
Base ten blocks: Physical or visual models representing place value: units (1), rods (10), flats (100)
- Identify the digit in each place value position
- Convert each digit to the corresponding base ten blocks
- Count the total number of each type of block needed
- Verify the representation equals the original number
243 has digits: 2 (hundreds), 4 (tens), 3 (ones)
Hundreds (2): 2 flats (each flat = 100)
Tens (4): 4 rods (each rod = 10)
Ones (3): 3 units (each unit = 1)
2 flats, 4 rods, 3 units
(2 × 100) + (4 × 10) + (3 × 1) = 200 + 40 + 3 = 243 ✓
243 is represented by 2 flats (200), 4 rods (40), and 3 units (3)
• Place value correspondence: Hundreds ↔ flats, tens ↔ rods, ones ↔ units
• Block value: Flat = 100, rod = 10, unit = 1
• Representation verification: Sum of block values equals original number
Show regrouping when necessary
Regrouping: Converting 10 of a smaller unit into 1 of the next larger unit
157 = 1 flat + 5 rods + 7 units
268 = 2 flats + 6 rods + 8 units
Flats: 1 + 2 = 3 flats
Rods: 5 + 6 = 11 rods
Units: 7 + 8 = 15 units
15 units = 1 rod + 5 units (regroup 10 units to 1 rod)
New count: 3 flats + (11+1) rods + 5 units = 3 flats + 12 rods + 5 units
12 rods = 1 flat + 2 rods (regroup 10 rods to 1 flat)
Final count: (3+1) flats + 2 rods + 5 units = 4 flats + 2 rods + 5 units
157 + 268 = 425, represented by 4 flats, 2 rods, and 5 units
• Regrouping rule: 10 units = 1 rod, 10 rods = 1 flat
• Addition principle: Add corresponding place values separately
• Carry-over: When sum ≥ 10, regroup to next higher place value
Show borrowing when necessary
Borrowing: Converting 1 of a larger unit into 10 of the next smaller unit
325 = 3 flats + 2 rods + 5 units
We need to subtract: 1 flat + 7 rods + 8 units
But we only have 5 units, so we need to borrow
Cannot subtract 8 units from 5 units, so borrow 1 rod (10 units)
325 becomes: 3 flats + 1 rod + 15 units
Cannot subtract 7 rods from 1 rod, so borrow 1 flat (10 rods)
325 becomes: 2 flats + 11 rods + 15 units
Flats: 2 - 1 = 1 flat
Rods: 11 - 7 = 4 rods
Units: 15 - 8 = 7 units
Total: 1 flat + 4 rods + 7 units = 147
325 - 178 = 147, represented by 1 flat, 4 rods, and 7 units
• Borrowing rule: 1 flat = 10 rods, 1 rod = 10 units
• Subtraction principle: Subtract corresponding place values separately
• Borrow when needed: When minuend digit < subtrahend digit
Base ten blocks: Concrete manipulatives representing place value concepts
Regrouping: Converting between place values (10 units = 1 rod, 10 rods = 1 flat)
Borrowing: Converting a higher place value to 10 of the next lower place value
Place value: The value of a digit based on its position in a number
Base ten system: Number system where each place value is 10 times the previous
- Representation: Convert numbers to corresponding base ten blocks
- Operation setup: Arrange blocks for the intended operation
- Execution: Perform the operation using block manipulation
- Regrouping/Borrowing: Convert between place values as needed
- Verification: Check that the result matches the expected answer
• Base ten block values: Unit = 1, Rod = 10, Flat = 100
• Regrouping: 10 units = 1 rod, 10 rods = 1 flat
• Borrowing: 1 flat = 10 rods, 1 rod = 10 units
• Place value: Each position is 10 times the previous position
a) 3 flats + 0 rods + 7 units = ?
b) 456 = ? flats + ? rods + ? units
Conversion: Changing between physical block representations and numerical form
3 flats = 3 × 100 = 300
0 rods = 0 × 10 = 0
7 units = 7 × 1 = 7
Total: 300 + 0 + 7 = 307
456: 4 in hundreds place → 4 flats
5 in tens place → 5 rods
6 in ones place → 6 units
Part a: 307 = 3 flats + 0 rods + 7 units ✓
Part b: (4 × 100) + (5 × 10) + (6 × 1) = 400 + 50 + 6 = 456 ✓
a) 3 flats + 0 rods + 7 units = 307
b) 456 = 4 flats + 5 rods + 6 units
• Place value conversion: Each digit position corresponds to a specific block type
• Block value multiplication: Multiply digit by block value (1, 10, or 100)
• Summation: Add all converted values to get the final number
How many total units does she have now?
Word problem solving: Applying base ten block concepts to real-world scenarios
Sarah starts with: 2 flats + 3 rods + 5 units
She trades: 1 rod + 8 units
But she only has 5 units, so she needs to borrow
Borrow 1 rod (10 units): Now has 2 rods + 15 units
Trade: 1 rod + 8 units = 0 rods + 7 units
Remaining: 2 flats + 2 rods + 7 units
She receives more rods in exchange, but question asks for units
Final units: 7
Sarah has 7 units remaining after the trade
• Problem translation: Convert word problem to mathematical representation
• Borrowing application: Use when insufficient units available
• Block manipulation: Apply base ten block rules to solve
Base ten blocks: Concrete manipulatives representing the decimal system (base 10)
Mathematical modeling: Using physical objects to represent abstract mathematical concepts
Place value system: Each position in a number has a value 10 times the position to its right
Concrete-pictorial-abstract progression: Moving from physical objects to mental concepts
Regrouping: Converting between equivalent representations (10 ones = 1 ten)
- Concrete phase: Manipulate actual base ten blocks
- Pictorial phase: Draw or visualize block representations
- Abstract phase: Work with numbers without physical models
- Connection: Link concrete actions to abstract algorithms
• Base ten relationship: Each place value is 10 times the previous
• Block equivalences: 10 units = 1 rod, 10 rods = 1 flat, 10 flats = 1 cube
• Regrouping formula: n × (value of smaller unit) = (n ÷ 10) × (value of larger unit)
• Number representation: abc = a×100 + b×10 + c×1
\(B_1: 1 unit = 1\)
\(B_2: 1 rod = 10 units\)
\(B_3: 1 flat = 100 units\)
\(B_4: 1 cube = 1000 units\)
Analysis: The visualization shows the exponential relationship between base ten block types.
- \(B_1\): 1 unit represents the base unit
- \(B_2\): 1 rod equals 10 units (10¹)
- \(B_3\): 1 flat equals 100 units (10²)
- \(B_4\): 1 cube equals 1000 units (10³)