Compose: To put together parts to make a whole number (e.g., 3 tens + 5 ones = 35)
Decompose: To break apart a number into its parts (e.g., 47 = 4 tens + 7 ones)
Place Value: The value of a digit based on its position in a number
Tens Place: The leftmost digit in a 2-digit number representing groups of 10
Ones Place: The rightmost digit in a 2-digit number representing individual units
Assessment: Testing and evaluating understanding of mathematical concepts
Base-10: Our number system based on groups of 10
• Rule 1: 1 ten = 10 ones (10 individual units = 1 group of 10)
• Rule 2: The position of a digit determines its value
• Rule 3: Tens place value is 10 times the ones place value
• Rule 4: Every 10 ones can be regrouped as 1 ten
• Rule 5: Numbers can be decomposed into tens + ones
• Law: Composition and decomposition are inverse operations
- Step 1: Identify the tens and ones parts
- Step 2: Convert tens to their value (tens × 10)
- Step 3: Keep ones as their value
- Step 4: Add tens and ones together
- Step 5: Write the final number
- Step 1: Identify the number to decompose
- Step 2: Look at the tens digit (left digit)
- Step 3: Look at the ones digit (right digit)
- Step 4: Express as: number = tens + ones
- Step 5: Verify by recomposing
• Compose and decompose are opposite operations
• Tens place value is always 10 times the ones place
• 10 individual units can be grouped as 1 ten
• Practice both operations to strengthen understanding
• Always verify your answers by checking both directions
What number do you get?
4 tens = 4 × 10 = 40
7 ones = 7 × 1 = 7
40 + 7 = 47
When we compose 4 tens (40) and 7 ones (7), we get 47. The 4 goes in the tens place and the 7 goes in the ones place.
How many tens and how many ones?
Number: 63
63 has 6 tens and 3 ones
63 = 60 + 3
63 = 6 tens + 3 ones
When we decompose 63, we break it into 6 tens (60) and 3 ones (3). The 6 in the tens place represents 60, and the 3 in the ones place represents 3.
Then decompose that number back to check your work.
5 tens + 2 ones = 50 + 2 = 52
52 has 5 tens and 2 ones
5 tens = 50
2 ones = 2
50 + 2 = 52 ✓
52 = 5 tens + 2 ones
We composed 5 tens (50) and 2 ones (2) to get 52. Then we decomposed 52 back to 5 tens and 2 ones to verify our answer is correct.
Show both processes clearly.
89 has 8 tens and 9 ones
89 = 80 + 9
89 = 8 tens + 9 ones
89 = 80 + 9 = 89 ✓
8 tens + 9 ones = 89
We decomposed 89 into 8 tens (80) and 9 ones (9), then composed those parts back to get 89. This confirms our understanding of place value.
Show the full cycle: compose → decompose → verify.
3 tens + 4 ones = 30 + 4 = 34
34 has 3 tens and 4 ones
34 = 30 + 4
34 = 3 tens + 4 ones
Original: 3 tens + 4 ones → Compose → 34
Then: 34 → Decompose → 3 tens + 4 ones
Full cycle completed successfully!
34 = 3 tens + 4 ones
This exercise demonstrates the inverse relationship between composing and decomposing. Starting with 3 tens and 4 ones, we composed them to get 34. Then we decomposed 34 back to 3 tens and 4 ones, completing the full cycle and verifying our understanding.