Compose: To put together parts to make a whole number (e.g., 3 tens + 5 ones = 35)
Decompose: To break apart a number into its parts (e.g., 47 = 4 tens + 7 ones)
Place Value: The value of a digit based on its position in a number
Tens Place: The leftmost digit in a 2-digit number representing groups of 10
Ones Place: The rightmost digit in a 2-digit number representing individual units
Inverse Operations: Operations that undo each other (compose and decompose)
Base-10: Our number system based on groups of 10
• Rule 1: 1 ten = 10 ones (10 individual units = 1 group of 10)
• Rule 2: The position of a digit determines its value
• Rule 3: Tens place value is 10 times the ones place value
• Rule 4: Every 10 ones can be regrouped as 1 ten
• Rule 5: Numbers can be decomposed into tens + ones
• Law: Composition and decomposition are inverse operations
- Step 1: Identify the tens and ones parts
- Step 2: Convert tens to their value (tens × 10)
- Step 3: Keep ones as their value
- Step 4: Add tens and ones together
- Step 5: Write the final number
- Step 1: Identify the number to decompose
- Step 2: Look at the tens digit (left digit)
- Step 3: Look at the ones digit (right digit)
- Step 4: Express as: number = tens + ones
- Step 5: Verify by recomposing
• Compose and decompose are opposite operations
• Tens place value is always 10 times the ones place
• 10 individual units can be grouped as 1 ten
• Practice both operations to strengthen understanding
• Always verify your answers by checking both directions
What number do you get?
2 tens = 2 × 10 = 20
8 ones = 8 × 1 = 8
20 + 8 = 28
When we compose 2 tens (20) and 8 ones (8), we get 28. The 2 goes in the tens place and the 8 goes in the ones place.
How many tens and how many ones?
Number: 54
54 has 5 tens and 4 ones
54 = 50 + 4
54 = 5 tens + 4 ones
When we decompose 54, we break it into 5 tens (50) and 4 ones (4). The 5 in the tens place represents 50, and the 4 in the ones place represents 4.
Then decompose that number back to check your work.
7 tens + 3 ones = 70 + 3 = 73
73 has 7 tens and 3 ones
7 tens = 70
3 ones = 3
70 + 3 = 73 ✓
73 = 7 tens + 3 ones
We composed 7 tens (70) and 3 ones (3) to get 73. Then we decomposed 73 back to 7 tens and 3 ones to verify our answer is correct.
Show both processes clearly.
91 has 9 tens and 1 one
91 = 90 + 1
91 = 9 tens + 1 one
91 = 90 + 1 = 91 ✓
9 tens + 1 one = 91
We decomposed 91 into 9 tens (90) and 1 one (1), then composed those parts back to get 91. This confirms our understanding of place value.
Show the full cycle: compose → decompose → verify.
4 tens + 6 ones = 40 + 6 = 46
46 has 4 tens and 6 ones
46 = 40 + 6
46 = 4 tens + 6 ones
Original: 4 tens + 6 ones → Compose → 46
Then: 46 → Decompose → 4 tens + 6 ones
Full cycle completed successfully!
46 = 4 tens + 6 ones
This exercise demonstrates the inverse relationship between composing and decomposing. Starting with 4 tens and 6 ones, we composed them to get 46. Then we decomposed 46 back to 4 tens and 6 ones, completing the full cycle and verifying our understanding.