This is question 1 from the advanced worksheet. Follow the steps to solve.
This problem involves subtracting three-digit numbers with regrouping.
Multi-digit subtraction: Subtracting numbers with more than one digit, often requiring regrouping
Regrouping: Trading tens for ones when the top digit is smaller than the bottom digit
Note: This problem requires borrowing across place values.
- Align the numbers by place value
- Subtract ones place: if top digit is smaller, borrow from tens
- Subtract tens place: if needed, borrow from hundreds
- Subtract hundreds place
427 - 189: In ones place, 7 < 9, so borrow 1 ten (making it 17 - 9 = 8). In tens place, 1 < 8, so borrow 1 hundred (making it 11 - 8 = 3). In hundreds place, 3 - 1 = 2.
There are 238 books left in the library.
• Regrouping: When top digit is smaller, borrow from the next place value
• Multi-digit subtraction: 427 - 189 = 238 books remain
• Verification: Add the borrowed amount to the remaining: 238 + 189 = 427 ✓
• Practice Tip: Always check if regrouping is needed before subtracting each place
- 532 - 278 = 254 - Practice with different regrouping
- 614 - 347 = 267 - More complex borrowing
- 805 - 296 = 509 - Practice with zeros
- Check each place value before subtracting to see if regrouping is needed
- Always borrow from the next higher place value when needed
- Verify your answer by adding the result to the subtracted amount
Q: What if I can't borrow from the next place?
A: If the next place value is 0, continue borrowing from the next non-zero place value.
Q: How do I know when to regroup?
A: When the top digit in any place is smaller than the bottom digit, regrouping is needed.
This is question 2 from the advanced worksheet. Follow the steps to solve.
This problem involves subtracting across zeros with multiple regrouping steps.
Subtraction with regrouping: When subtracting, if the top digit is smaller than the bottom digit in any place value, borrow from the next higher place value
Borrowing across zeros: When a place value is zero, continue borrowing from the next non-zero place value
Note: This problem requires multiple regrouping steps.
- Look at the ones place: 3 < 7, so borrow from tens
- Tens place is 0, so borrow from hundreds first
- Then borrow from the new tens value to subtract ones
- Continue subtracting each place value
503 - 267: In ones place, 3 < 7, so need to borrow. Since tens is 0, borrow 1 from hundreds (making it 4), then borrow 1 ten (making it 10), then subtract ones: 13 - 7 = 6. Continue with tens: 9 - 6 = 3, and hundreds: 4 - 2 = 2.
503 - 267
3 < 7, so borrow: 13 - 7 = 6
After borrowing, 9 - 6 = 3
After borrowing, 4 - 2 = 2
Sarah has 236 stamps left.
• Regrouping across zeros: When borrowing from zero, continue to the next place
• Subtraction: 503 - 267 = 236 stamps remain
• Verification: Add the given away amount to remaining: 236 + 267 = 503 ✓
• Practice Tip: When subtracting across zeros, plan your borrowing steps ahead
- 600 - 245 = 355 - Practice with zeros in tens and ones
- 402 - 187 = 215 - More borrowing across zeros
- 801 - 356 = 445 - Complex regrouping scenarios
- When subtracting across zeros, work from right to left planning your borrows
- Mark each place where you borrow to keep track
- Always verify by adding your answer to the subtracted amount
Q: What if I have to borrow from a zero?
A: Borrow from the next non-zero place value, turning the zero into 10.
Q: How do I keep track of multiple borrows?
A: Mark each place where you borrow and update the values as you go.
This is question 3 from the advanced worksheet. Follow the steps to solve.
This problem involves subtracting decimal amounts with regrouping.
Money subtraction: Subtracting dollar and cent amounts, treating the decimal point as a separator
Decimal subtraction: Align decimal points and subtract as whole numbers
Note: Treat money problems like regular subtraction, keeping the decimal point aligned.
- Align the decimal points vertically
- Subtract cents first: if top is smaller, borrow from dollars
- Subtract dollars
- Include the dollar sign in the answer
$7.50 - $3.85: In cents place, 50¢ < 85¢, so borrow $1 (100¢), making it 150¢ - 85¢ = 65¢. In dollars place, after borrowing, 6 - 3 = 3.
$7.50 - $3.85
50¢ < 85¢, so borrow $1: 150¢ - 85¢ = 65¢
After borrowing, $6 - $3 = $3
$3.65 remaining
Emma has $3.65 left.
• Decimal alignment: Keep decimal points aligned vertically
• Money subtraction: $7.50 - $3.85 = $3.65 remains
• Verification: Add the spent amount to remaining: $3.65 + $3.85 = $7.50 ✓
• Practice Tip: Think of dollars and cents separately when borrowing
- $5.25 - $2.75 = $2.50 - Practice with round cents
- $10.00 - $4.35 = $5.65 - More complex borrowing
- $8.75 - $3.99 = $4.76 - Practice with pennies
- Always align decimal points when subtracting money
- Think of $1 as 100¢ when borrowing across the decimal
- Include the dollar sign in your final answer
Q: What if I need to borrow from dollars to cents?
A: Borrow $1, which equals 100¢, and add it to the cents column.
Q: Should I write the dollar sign in my calculation?
A: Include the dollar sign in the final answer, but you can work without it during calculation.
This is question 4 from the advanced worksheet. Follow the steps to solve.
This problem involves subtracting three-digit measurements with regrouping.
Measurement subtraction: Subtracting lengths, distances, or other measured quantities
Centimeters: A unit of length equal to 1/100 of a meter
Note: Same subtraction rules apply to measurements as to regular numbers.
- Identify the starting measurement and what's being subtracted
- Align numbers by place value
- Subtract using regrouping if needed
- Include the unit (cm) in the answer
845 - 368: In ones place, 5 < 8, so borrow from tens. In tens place, 3 < 6, so borrow from hundreds. Result: 477 cm.
Original: 845 cm, Cut off: 368 cm
845 - 368
Need to borrow in ones and tens places
477 cm remaining
The remaining piece of rope is 477 cm long.
• Measurement subtraction: Same rules as regular subtraction
• Regrouping: Borrow when top digit is smaller than bottom digit
• Units: Always include the unit (cm) in your answer
• Verification: Add the cut-off length to remaining: 477 + 368 = 845 ✓
- 623 m - 279 m = 344 m - Practice with meters
- 950 kg - 486 kg = 464 kg - Weight subtraction
- 705 L - 287 L = 418 L - Volume subtraction
- Always include the unit in your final answer
- Same subtraction rules apply to all measurements
- Check that your answer is reasonable (smaller than the original)
Q: What if the measurements have different units?
A: Convert to the same unit before subtracting.
Q: Do I need to include units during calculation?
A: You can work without units during calculation, but include them in the final answer.
This is question 5 from the advanced worksheet. Follow the steps to solve.
This problem involves subtracting time measurements with regrouping.
Time subtraction: Subtracting durations measured in minutes, hours, etc.
Minutes: Units of time equal to 60 seconds
Note: Time subtraction follows the same principles as regular subtraction.
- Identify the total time and the time elapsed
- Set up the subtraction equation
- Subtract using regrouping if needed
- Include the unit (minutes) in the answer
125 - 78: In ones place, 5 < 8, so borrow from tens. In tens place, 1 < 7, so borrow from hundreds. Result: 47 minutes.
Total: 125 min, Watched: 78 min
125 - 78 = ?
Need to borrow in ones and tens places
47 minutes remaining
There were 47 minutes of the movie left.
• Time subtraction: Same rules as regular subtraction
• Regrouping: Borrow when top digit is smaller than bottom digit
• Units: Always include the unit (minutes) in your answer
• Verification: Add the watched time to remaining: 47 + 78 = 125 ✓
- 95 min - 37 min = 58 min - Practice with time
- 150 s - 89 s = 61 s - Seconds subtraction
- 200 days - 145 days = 55 days - Days subtraction
- Same subtraction rules apply to time as to regular numbers
- Always include the time unit in your final answer
- Check that your answer is reasonable
Q: What if I need to subtract across hour boundaries?
A: Convert hours to minutes first, then subtract normally.
Q: Can time be negative?
A: No, time cannot be negative. If you get a negative result, check your calculation.