\(123 + 345\)
Three-digit number: A number with three digits, representing hundreds, tens, and ones places
- Line up numbers by place value (ones under ones, tens under tens, hundreds under hundreds)
- Add the ones column: \(3 + 5 = 8\)
- Add the tens column: \(2 + 4 = 6\)
- Add the hundreds column: \(1 + 3 = 4\)
- Write the answer: \(468\)
\(\begin{array}{r} H \ T \ O \\ 1 \ 2 \ 3 \\ + 3 \ 4 \ 5 \\ \hline \end{array}\)
\(3 + 5 = 8\) (write 8 in the ones place)
\(2 + 4 = 6\) (write 6 in the tens place)
\(1 + 3 = 4\) (write 4 in the hundreds place)
\(123 + 345 = 468\)
• Place value: Align digits by their place values (hundreds, tens, ones)
• Column addition: Add digits in the same place value columns separately
• No regrouping: Since no column sum exceeds 9, no carrying is needed
\(204 + 135\)
Zero in place value: Zero holds a place in the number but has no value when added
\(\begin{array}{r} H \ T \ O \\ 2 \ 0 \ 4 \\ + 1 \ 3 \ 5 \\ \hline \end{array}\)
\(4 + 5 = 9\) (write 9 in the ones place)
\(0 + 3 = 3\) (write 3 in the tens place)
\(2 + 1 = 3\) (write 3 in the hundreds place)
\(204 + 135 = 339\)
• Zero property: Adding zero doesn't change the value (\(0 + 3 = 3\))
• Place value: Even if there's a zero, still align by place value
• No regrouping: Since no column sum exceeds 9, no carrying is needed
\(320 + 45\)
Regrouping (carrying): When the sum of a column is 10 or more, we carry the extra value to the next column
Write the numbers so ones are under ones, tens under tens, etc.:\(\begin{array}{r} H \ T \ O \\ 3 \ 2 \ 0 \\ + \phantom{3} \ 4 \ 5 \\ \hline \end{array}\)
\(0 + 5 = 5\) (write 5 in the ones place)
\(2 + 4 = 6\) (write 6 in the tens place)
\(3 + 0 = 3\) (write 3 in the hundreds place)
\(320 + 45 = 365\)
• Place value alignment: Align digits by their place values even when numbers have different digit counts
• Treating missing digits: Think of 45 as 045 when adding to 320
• No regrouping: Since no column sum exceeds 9, no carrying is needed
Three-digit number: A number with three digits representing hundreds, tens, and ones places
Place value: The value of a digit based on its position in the number
Regrouping (carrying): Moving a group of ten from one place value to the next higher place value
- Align numbers: Put numbers in columns by place value
- Add ones column: Add the digits in the ones place
- Add tens column: Add the digits in the tens place
- Add hundreds column: Add the digits in the hundreds place
- Write the answer: Combine the results from each column
• Place value alignment: \(123 + 345 = \begin{array}{r} 123 \\ + 345 \\ \hline 468 \end{array}\)
• Column-wise addition: Add ones, tens, then hundreds separately
• No regrouping condition: Each column sum must be ≤ 9
• Zero handling: \(204 + 135 = \begin{array}{r} 204 \\ + 135 \\ \hline 339 \end{array}\)
\(400 + 302\)
Multiple zeros: When adding numbers with zeros in different place values
\(\begin{array}{r} H \ T \ O \\ 4 \ 0 \ 0 \\ + 3 \ 0 \ 2 \\ \hline \end{array}\)
\(0 + 2 = 2\) (write 2 in the ones place)
\(0 + 0 = 0\) (write 0 in the tens place)
\(4 + 3 = 7\) (write 7 in the hundreds place)
\(400 + 302 = 702\)
• Zero addition: Adding zeros doesn't change the value
• Place value: Still align by place value even with multiple zeros
• No regrouping: Since no column sum exceeds 9, no carrying is needed
Word problem: A real-world scenario that requires mathematical calculation to solve
Fiction books = 234, Non-fiction books = 145
We need to find the total, so we add: 234 + 145
\(\begin{array}{r} H \ T \ O \\ 2 \ 3 \ 4 \\ + 1 \ 4 \ 5 \\ \hline \end{array}\)
Ones: \(4 + 5 = 9\), Tens: \(3 + 4 = 7\), Hundreds: \(2 + 1 = 3\)
There are 379 books in total.
• Real-world application: Connect math to everyday situations
• Problem-solving: Identify what needs to be calculated
• Verification: Check that 234 + 145 = 379 makes sense
Three-digit number: A number with three digits representing hundreds, tens, and ones places
Place value: The value of a digit based on its position in the number (hundreds, tens, ones)
Regrouping (carrying): Moving a group of ten from one place value to the next higher place value
- Align numbers: Put numbers in columns by place value
- Add ones column: Add the digits in the ones place
- Add tens column: Add the digits in the tens place
- Add hundreds column: Add the digits in the hundreds place
- Write the answer: Combine the results from each column
• Place value alignment: \(123 + 345 = \begin{array}{r} 123 \\ + 345 \\ \hline 468 \end{array}\)
• Column-wise addition: Add ones, tens, then hundreds separately
• No regrouping condition: Each column sum must be ≤ 9
• Zero handling: \(204 + 135 = \begin{array}{r} 204 \\ + 135 \\ \hline 339 \end{array}\)
\(f_1(x) = 100x\) (hundreds)
\(f_2(x) = 10x\) (tens)
\(f_3(x) = x\) (ones)
Analysis: The chart shows how three-digit numbers decompose into place value components.
- \(f_1(x) = 100x\) (Hundreds place: 100 × digit value)
- \(f_2(x) = 10x\) (Tens place: 10 × digit value)
- \(f_3(x) = x\) (Ones place: 1 × digit value)