\(423 - 157\)
Regrouping (borrowing): When the top digit in a column is smaller than the bottom digit, we borrow from the next higher place value
- Line up numbers by place value (ones under ones, tens under tens, hundreds under hundreds)
- Subtract ones column: \(3 - 7\), since 3 < 7, borrow 1 from tens column (3 becomes 13, 2 becomes 1), so \(13 - 7 = 6\)
- Subtract tens column: \(1 - 5\), since 1 < 5, borrow 1 from hundreds column (1 becomes 11, 4 becomes 3), so \(11 - 5 = 6\)
- Subtract hundreds column: \(3 - 1 = 2\)
- Write the answer: \(266\)
\(\begin{array}{r} H \ T \ O \\ 4 \ 2 \ 3 \\ - 1 \ 5 \ 7 \\ \hline \end{array}\)
\(3 - 7\): Since 3 < 7, borrow 1 from tens column (2 becomes 1, 3 becomes 13), so \(13 - 7 = 6\)
\(1 - 5\): Since 1 < 5, borrow 1 from hundreds column (4 becomes 3, 1 becomes 11), so \(11 - 5 = 6\)
\(3 - 1 = 2\)
\(423 - 157 = 266\)
• Place value: Align digits by their place values (hundreds, tens, ones)
• Regrouping rule: When top digit < bottom digit, borrow 1 from next column
• Borrow effect: Borrowed column decreases by 1, borrowing column increases by 10
\(502 - 186\)
Multiple regrouping: When regrouping is needed in more than one column during the same subtraction
\(\begin{array}{r} H \ T \ O \\ 5 \ 0 \ 2 \\ - 1 \ 8 \ 6 \\ \hline \end{array}\)
\(2 - 6\): Since 2 < 6, borrow 1 from tens column (0 becomes 10, 2 becomes 12), so \(12 - 6 = 6\)
\(0 - 8\): Since 0 < 8, borrow 1 from hundreds column (5 becomes 4, 0 becomes 10), so \(10 - 8 = 2\)
\(4 - 1 = 3\)
\(502 - 186 = 316\)
• Multiple regrouping: Regroup in each column where top digit < bottom digit
• Sequential borrowing: Borrow from next higher column when needed
• Zero handling: When borrowing from zero, continue to the next non-zero column
\(600 - 247\)
Regrouping with zeros: When subtracting requires regrouping and one or more of the numbers contain zeros
\(\begin{array}{r} H \ T \ O \\ 6 \ 0 \ 0 \\ - 2 \ 4 \ 7 \\ \hline \end{array}\)
\(0 - 7\): Since 0 < 7, borrow 1 from tens column, but tens is 0, so borrow from hundreds (6 becomes 5, 0 becomes 10, then borrow 1 from tens: 10 becomes 9, 0 becomes 10), so \(10 - 7 = 3\)
\(9 - 4 = 5\)
\(5 - 2 = 3\)
\(600 - 247 = 353\)
• Zero handling: When borrowing from zero, continue to the next non-zero column
• Chain borrowing: Borrow sequentially through zeros to reach a non-zero digit
• Place value preservation: Maintain correct place value after regrouping
Three-digit number: A number with three digits representing hundreds, tens, and ones places
Place value: The value of a digit based on its position in the number
Regrouping (borrowing): Moving a group of ten from one place value to the next lower place value
- Align numbers: Put numbers in columns by place value
- Subtract ones column: If top digit < bottom digit, borrow 1 from tens column
- Subtract tens column: If top digit < bottom digit, borrow 1 from hundreds column
- Subtract hundreds column: Subtract the digits
- Write the answer: Combine the results from each column
• Borrowing condition: \(3 < 7\) → borrow from tens
• Borrow effect: \(2 - 1 = 1\), \(3 + 10 = 13\)
• Sequential processing: Process each column before moving to the next
• Zero handling: When borrowing from zero, continue to next non-zero column
\(703 - 268\)
Multiple regrouping: When regrouping occurs in more than one column during the same subtraction
\(\begin{array}{r} H \ T \ O \\ 7 \ 0 \ 3 \\ - 2 \ 6 \ 8 \\ \hline \end{array}\)
\(3 - 8\): Since 3 < 8, borrow 1 from tens column, but tens is 0, so borrow from hundreds (7 becomes 6, 0 becomes 10, then borrow 1 from tens: 10 becomes 9, 3 becomes 13), so \(13 - 8 = 5\)
\(9 - 6 = 3\)
\(6 - 2 = 4\)
\(703 - 268 = 435\)
• Multiple regrouping: Regroup in each column where top digit < bottom digit
• Chain borrowing: Borrow sequentially through zeros to reach a non-zero digit
• Sequential processing: Process each column from right to left
Word problem: A real-world scenario that requires mathematical calculation to solve
Starting toys = 520, Toys sold = 184
We need to find the remaining toys, so we subtract: 520 - 184
\(\begin{array}{r} H \ T \ O \\ 5 \ 2 \ 0 \\ - 1 \ 8 \ 4 \\ \hline \end{array}\)
Ones: \(0 - 4\): Since 0 < 4, borrow 1 from tens (2 becomes 1, 0 becomes 10), so \(10 - 4 = 6\)
Tens: \(1 - 8\): Since 1 < 8, borrow 1 from hundreds (5 becomes 4, 1 becomes 11), so \(11 - 8 = 3\)
Hundreds: \(4 - 1 = 3\)
336 toys are left in stock.
• Real-world application: Connect math to everyday situations
• Problem-solving: Identify what needs to be calculated
• Regrouping: Apply borrowing rules when top digit < bottom digit
Three-digit number: A number with three digits representing hundreds, tens, and ones places
Place value: The value of a digit based on its position in the number (hundreds, tens, ones)
Regrouping (borrowing): Moving a group of ten from one place value to the next lower place value when the top digit is smaller than the bottom digit
- Align numbers: Put numbers in columns by place value
- Subtract ones column: If top digit < bottom digit, borrow 1 from tens column
- Subtract tens column: If top digit < bottom digit, borrow 1 from hundreds column
- Subtract hundreds column: Subtract the digits
- Write the answer: Combine the results from each column
• Borrowing condition: If top digit < bottom digit, borrow from next higher column
• Borrow effect: Decrease borrowed column by 1, increase borrowing column by 10
• Sequential processing: Process columns from right to left
• Multiple regrouping: Apply borrowing rules to each column independently
\(f_1(x) = x\) (before regrouping)
\(f_2(x) = x + 10\) (after borrowing)
\(f_3(x) = x - 1\) (decreased column)
Analysis: The chart shows how regrouping works in three-digit subtraction.
- \(f_1(x) = x\) (original value before regrouping)
- \(f_2(x) = x + 10\) (value increased after borrowing)
- \(f_3(x) = x - 1\) (value decreased after lending)