Expanded Form: Writing a number as the sum of its place values (e.g., 84 = 80 + 4).
- Write each number in expanded form
- Add the tens together
- Add the ones together
- Combine the sums
- Regroup if necessary
84 = 80 + 4 and 17 = 10 + 7
80 + 10 = 90
4 + 7 = 11
90 + 11 = 101
84 + 17 = 101
• Expanded Form: Expressing numbers as the sum of their place values
• Place Value Addition: Adding digits with the same place value
• Regrouping: When ones sum to 10+, convert to tens and ones
Regrouping Strategy: Converting 10 ones to 1 ten when adding, or 1 ten to 10 ones when subtracting.
58 = 50 + 8 and 37 = 30 + 7
50 + 30 = 80
8 + 7 = 15
15 ones = 10 ones + 5 ones = 1 ten + 5 ones
80 + 10 = 90, then 90 + 5 = 95
58 + 37 = 95
• Place Value Addition: Add digits with the same place value
• Regrouping: When ones sum to 10 or more, convert to tens and ones
• Number Composition: Reassemble the final sum from its components
Subtraction with Regrouping: Converting 1 ten to 10 ones when the top ones digit is smaller than the bottom ones digit.
72 = 70 + 2 and 38 = 30 + 8
2 - 8 cannot be done, so we need to regroup
Take 1 ten from 70 (leaving 60) and add to 2 ones: 60 + 12
60 - 30 = 30 and 12 - 8 = 4
30 + 4 = 34
72 - 38 = 34
• Place Value Subtraction: Subtract digits with the same place value
• Regrouping: When the top digit is smaller, borrow from the next higher place
• Number Composition: Reassemble the final difference from its components
Place Value: The value of a digit based on its position in a number (ones, tens, hundreds)
Expanded Form: Writing a number as the sum of its place values (e.g., 84 = 80 + 4)
Regrouping: Converting from one place value to another (borrowing in subtraction, carrying in addition)
Decomposing: Breaking a number into its component parts (tens and ones)
- Identify place values: Determine the tens and ones in each number
- Separate by place: Work with tens and ones separately
- Perform operations: Add or subtract digits in the same place
- Regroup when necessary: Borrow or carry between places
- Combine results: Put the tens and ones back together
• In 2-digit numbers, the left digit is the tens place, right digit is the ones place
• When adding, add tens to tens and ones to ones
• When subtracting, subtract tens from tens and ones from ones
• Regroup when the top digit is smaller than the bottom digit in subtraction
• 1 ten = 10 ones (for regrouping purposes)
Mixed Operations Strategy: Perform operations sequentially using place-value methods.
46 = 40 + 6, 29 = 20 + 9, so (40 + 20) + (6 + 9) = 60 + 15 = 75
75 = 70 + 5, 18 = 10 + 8
Now we have (60 + 15) - (10 + 8)
60 - 10 = 50, and 15 - 8 = 7
50 + 7 = 57
46 + 29 - 18 = 57
• Order of Operations: Perform operations from left to right
• Place Value Strategy: Use decomposition for each operation
• Regrouping: Apply when needed in each step
Comparison Strategy: Solve each expression using place-value methods, then compare the results.
63 = 60 + 3, 27 = 20 + 7
Now we have (50 + 13) - (20 + 7)
50 - 20 = 30, and 13 - 7 = 6
30 + 6 = 36
58 = 50 + 8, 23 = 20 + 3, so (50 - 20) + (8 - 3) = 30 + 5 = 35
36 > 35, so 63 - 27 is greater
63 - 27 is greater than 58 - 23
• Place Value Subtraction: Apply decomposition method to both expressions
• Comparison: Once both expressions are simplified, compare the results
• Regrouping: Apply when needed in each expression
Place Value: The value of a digit based on its position in a number (ones, tens, hundreds)
Expanded Form: Writing a number as the sum of its place values (e.g., 84 = 80 + 4)
Regrouping: Converting between place values (1 ten = 10 ones)
Decomposing: Breaking a number into its component parts (tens and ones)
- Identify place values: Look at each digit and determine its value
- Separate by place: Group tens and ones separately
- Perform operations: Work with tens and ones separately
- Regroup when necessary: Convert between places when needed
- Combine results: Put the final answer together
• Decompose numbers into tens and ones before operating
• Add/subtract digits with the same place value
• Regroup when necessary (10 ones = 1 ten)
• Check your answer by using the inverse operation
• Use visual models to support understanding