\(63 - 27\)
Build 63 with 6 tens rods and 3 ones cubes. Try to take away 27 (2 tens and 7 ones). Since you only have 3 ones, you need to break apart 1 tens rod into 10 ones.
Regrouping: Also known as "borrowing", it's taking one group of ten from the tens place to add to the ones place when the top digit is smaller than the bottom digit
- Align numbers by place value (ones under ones, tens under tens)
- Compare ones digits: if top < bottom, regroup from tens
- Take 1 ten from tens place (subtract 1 from tens digit)
- Add 10 to the ones place (add 10 to ones digit)
- Subtract ones digits
- Subtract tens digits
\(\begin{array}{c@{}c@{}c} & 6 & 3 \\ - & 2 & 7 \\ \hline \end{array}\)
\(3 < 7\), so we need to regroup from tens place
Take 1 ten from the tens place (6 becomes 5) and add 10 to the ones place (3 becomes 13)
\(13 - 7 = 6\)
\(5 - 2 = 3\)
\(3\) tens and \(6\) ones equals \(36\)
\(63 - 27 = 36\)
• Regrouping rule: When top digit is smaller, borrow 1 from next higher place value
• Place value: 1 ten = 10 ones
• Adjustment: Reduce the higher place value by 1 after borrowing
\(50 - 26\)
Roll two dice to create a two-digit number (e.g., roll 5 and 0 to make 50). Roll again for the second number (2 and 6 to make 26). Solve the subtraction problem.
\(\begin{array}{c@{}c@{}c} & 5 & 0 \\ - & 2 & 6 \\ \hline \end{array}\)
\(0 < 6\), so we need to regroup from tens place
Take 1 ten from the tens place (5 becomes 4) and add 10 to the ones place (0 becomes 10)
\(10 - 6 = 4\)
\(4 - 2 = 2\)
\(2\) tens and \(4\) ones equals \(24\)
\(50 - 26 = 24\)
• Zero exception: Always regroup when ones digit is 0, regardless of tens comparison
• Regrouping: 1 ten = 10 ones
• Place value: Maintain proper alignment after regrouping
Read the word problem carefully. Identify key words that indicate subtraction. Set up the problem using the regrouping method learned in previous activities.
"She bought" means we need to subtract: \(72 - 38\)
\(\begin{array}{c@{}c@{}c} & 7 & 2 \\ - & 3 & 8 \\ \hline \end{array}\)
\(2 < 8\), so we need to regroup from tens place
Take 1 ten from the tens place (7 becomes 6) and add 10 to the ones place (2 becomes 12)
\(12 - 8 = 4\)
\(6 - 3 = 3\)
Emma has 34 dollars left.
Emma has 34 dollars left.
• Problem solving: Identify key words indicating operation ("bought" means subtract)
• Regrouping: Follow the same regrouping procedure as numerical problems
• Context: Answer must make sense in the word problem context
Build numbers with virtual blocks. Drag tens rods and ones cubes to represent numbers. Practice regrouping by breaking apart tens rods into ones cubes.
Roll dice to generate two-digit numbers. Solve subtraction problems quickly. Score points for correct answers and fastest times.
Match word problems with their corresponding subtraction equations. Solve the equations using regrouping methods.
Regrouping: Taking 1 from a higher place value and adding 10 to the lower place value
Place value: Position of a digit determines its value (tens, ones)
Minuend: The number being subtracted from (top number)
Subtrahend: The number being subtracted (bottom number)
Difference: The result of subtraction
- Align numbers: Put ones under ones, tens under tens
- Check ones digits: Compare top ones digit with bottom ones digit
- Regroup if needed: When top ones < bottom ones, borrow from tens
- Perform regrouping: Reduce tens by 1, increase ones by 10
- Subtract ones: Top ones minus bottom ones
- Subtract tens: Top tens minus bottom tens
- Combine results: Write tens digit followed by ones digit
• Two-digit number: \(AB = A \times 10 + B\)
• Regrouping rule: When \(B < D\), borrow 1 ten (\(A\) becomes \(A-1\), \(B\) becomes \(B+10\))
• Zero exception: When \(B = 0\), always regroup even if \(A > C\)
• Place value alignment: Align ones with ones, tens with tens
• Verification: Difference + Subtrahend = Minuend
Count the stars initially (81) and then count how many fell off (45). Use regrouping to find how many are left. Draw stars if needed to visualize the subtraction.
Quantity problems: Problems involving counting items that are added, removed, or compared
"Fell off" means we need to subtract: \(81 - 45\)
\(\begin{array}{c@{}c@{}c} & 8 & 1 \\ - & 4 & 5 \\ \hline \end{array}\)
\(1 < 5\), so we need to regroup from tens place
Take 1 ten from the tens place (8 becomes 7) and add 10 to the ones place (1 becomes 11)
\(11 - 5 = 6\)
\(7 - 4 = 3\)
There are 36 stars left.
There are 36 stars left.
• Quantity problems: Same as regular subtraction, apply context
• Regrouping: Follow the same regrouping procedure as numerical problems
• Context: Answer must make sense in the word problem context
This is a multi-step problem! First, add the books borrowed on both days. Then subtract the total from the original number. Use regrouping as needed in both steps.
Add Monday and Tuesday borrowings: \(28 + 19 = 47\)
\(94 - 47\)
\(\begin{array}{c@{}c@{}c} & 9 & 4 \\ - & 4 & 7 \\ \hline \end{array}\)
\(4 < 7\), so we need to regroup from tens place
Take 1 ten from the tens place (9 becomes 8) and add 10 to the ones place (4 becomes 14)
\(14 - 7 = 7\)
\(8 - 4 = 4\)
The library has 47 books left.
The library has 47 books left.
• Multi-step problems: Break into smaller parts and solve sequentially
• Order of operations: Solve addition first, then subtraction
• Regrouping: Apply regrouping when needed in the final calculation
Complete all activities to master two-digit subtraction with regrouping!
Two-digit numbers: Numbers from 10 to 99 with tens and ones place values
Regrouping: Taking 1 from the tens place to add 10 to the ones place when the top digit is smaller
Place value: The value of a digit based on its position (tens, ones)
Minuend: The number being subtracted from (the larger number)
Subtrahend: The number being subtracted (the smaller number)
Difference: The result of the subtraction
- Read the problem: Understand what is being asked
- Set up the equation: Write the minuend above the subtrahend
- Align by place value: Ones under ones, tens under tens
- Check ones place: Compare top ones digit with bottom ones digit
- Regroup if necessary: When top ones < bottom ones, take 1 from tens
- Adjust numbers: Reduce tens by 1, increase ones by 10
- Subtract ones: Perform the subtraction in the ones place
- Subtract tens: Perform the subtraction in the tens place
- Check your answer: Add the difference to the subtrahend
• Place value: Always align digits by place value
• Regrouping rule: When top digit is smaller, borrow 1 ten = 10 ones
• Zero exception: When ones digit is 0, always regroup
• Subtraction sequence: Subtract ones first, then tens
• Verification: Difference + Subtrahend = Minuend
\(62 - 37\): Since \(2 < 7\), regroup \(62\) to \(5\) tens and \(12\) ones
\(40 - 23\): Since \(0 < 3\), regroup \(40\) to \(3\) tens and \(10\) ones
\(75 - 32\): Since \(5 > 2\), no regrouping needed