57 - 23
Place value subtraction: Subtracting numbers by breaking them into tens and ones, then subtracting like place values
- Break each number into tens and ones
- Subtract the tens from tens
- Subtract the ones from ones
- Combine the results
57 = 50 + 7 (5 tens and 7 ones)
23 = 20 + 3 (2 tens and 3 ones)
50 - 20 = 30
7 - 3 = 4
30 + 4 = 34
57 - 23 = 34
• Place value: Separate tens and ones to make subtraction easier
• Like place values: Only subtract tens from tens and ones from ones
• Combining: Add the final tens and ones together
57 → 5 tens
23 → 2 tens
Subtract: 5 - 2 = 3 tens = 30
57 → 7 ones
23 → 3 ones
Subtract: 7 - 3 = 4 ones
30 + 4 = 34
Or: 3 tens + 4 ones = 34
62 - 38
Regrouping in subtraction: Borrowing 1 ten from the tens place to add 10 ones to the ones place when needed
62 = 60 + 2 (6 tens and 2 ones)
38 = 30 + 8 (3 tens and 8 ones)
2 ones - 8 ones: We cannot subtract 8 from 2!
We need to regroup!
Borrow 1 ten from 6 tens: 60 becomes 50
Add 10 to the ones: 2 + 10 = 12 ones
Now we have: 50 + 12 - 30 - 8
50 - 30 = 20
12 - 8 = 4
20 + 4 = 24
62 - 38 = 24
• Regrouping: When ones in minuend are less than ones in subtrahend, borrow from tens
• Place value: Separate tens and ones for easier calculation
• Subtraction: Subtract tens from tens and ones from ones
62 → 6 tens + 2 ones
38 → 3 tens + 8 ones
2 ones < 8 ones → Borrow 1 ten
62 → 5 tens + 12 ones
Tens: 5 - 3 = 2 tens
Ones: 12 - 8 = 4 ones
Answer: 24
70 - 30
Subtracting multiples of 10: Subtracting numbers that only have tens place values (no ones)
70 = 7 tens + 0 ones
30 = 3 tens + 0 ones
7 tens - 3 tens = 4 tens
0 ones - 0 ones = 0 ones
4 tens + 0 ones = 40
70 - 30 = 40
• Place value: Understand that multiples of 10 only have tens place
• Like place values: Only subtract tens from tens and ones from ones
• Zero ones: When subtracting multiples of 10, the ones place remains zero
70 → 7 tens
30 → 3 tens
Subtract: 7 - 3 = 4 tens = 40
70 → 0 ones
30 → 0 ones
Subtract: 0 - 0 = 0 ones
4 tens + 0 ones = 40
Place value: The value of a digit based on its position in a number
Tens place: The second digit from the right, representing groups of ten
Ones place: The rightmost digit, representing individual units
Regrouping: Converting 1 ten into 10 ones when subtracting
Minuend: The number being subtracted from (top number)
Subtrahend: The number being subtracted (bottom number)
Expanded form: Writing a number as the sum of its place values (e.g., 45 = 40 + 5)
- Recognize the numbers: Look at minuend and subtrahend and identify tens and ones
- Break apart numbers: Write each number in expanded form (tens + ones)
- Check for regrouping: If ones in minuend are less than ones in subtrahend, regroup
- Subtract tens from tens: Perform tens subtraction
- Subtract ones from ones: Perform ones subtraction
- Combine results: Add the final tens and ones together
• Place value formula: Two-digit number AB = A×10 + B
• Subtraction rule: (T₁ + O₁) - (T₂ + O₂) = (T₁ - T₂) + (O₁ - O₂)
• Regrouping rule: When O₁ < O₂, borrow 1 ten from T₁
• Like place values: Only subtract tens from tens and ones from ones
45 - 23 = (40 + 5) - (20 + 3) = (40 - 20) + (5 - 3) = 20 + 2 = 22
52 - 37 = (50 + 2) - (30 + 7) = (40 + 12) - (30 + 7) = (40 - 30) + (12 - 7) = 10 + 5 = 15
80 - 30 = (8 tens) - (3 tens) = 5 tens = 50
Word problems: Real-life situations requiring mathematical operations using place value strategies
Tom started with 43 stickers
He gave away 18 stickers
This is a subtraction problem: 43 - 18
43 = 40 + 3 (4 tens and 3 ones)
18 = 10 + 8 (1 ten and 8 ones)
3 ones - 8 ones: We cannot subtract 8 from 3!
We need to regroup!
Borrow 1 ten from 4 tens: 40 becomes 30
Add 10 to the ones: 3 + 10 = 13 ones
Now we have: 30 + 13 - 10 - 8
Tens: 30 - 10 = 20
Ones: 13 - 8 = 5
20 + 5 = 25
Tom has 25 stickers left.
Tom has 25 stickers left.
• Problem solving: Identify operation needed from context
• Place value: Break numbers into tens and ones
• Regrouping: When ones in minuend are less than ones in subtrahend
Started with: 43 stickers
Gave away: 18 stickers
Operation: Subtraction
43 = 40 + 3
18 = 10 + 8
Regroup: 43 = 30 + 13
Tens: 30 - 10 = 20
Ones: 13 - 8 = 5
Total: 25 stickers
Multi-step problems: Problems requiring multiple subtraction operations solved sequentially using place value strategies
Morning sales: 29 cupcakes
Afternoon sales: 17 cupcakes
Total sold: 29 + 17 = 46 cupcakes
85 = 80 + 5, 29 = 20 + 9
Check ones: 5 < 9 → need to regroup
85 = 70 + 15
Tens: 70 - 20 = 50
Ones: 15 - 9 = 6
50 + 6 = 56 cupcakes left after morning
Now subtract the afternoon sales: 56 - 17
56 = 50 + 6, 17 = 10 + 7
Check ones: 6 < 7 → need to regroup
56 = 40 + 16
Tens: 40 - 10 = 30
Ones: 16 - 7 = 9
30 + 9 = 39 cupcakes left
The bakery has 39 cupcakes left.
The bakery has 39 cupcakes left.
• Order of operations: Work from left to right for subtraction
• Place value: Break each number into tens and ones
• Regrouping: Apply when necessary in each operation
Started with: 85 cupcakes
85 - 29
85 = 70 + 15
29 = 20 + 9
Result: 56 cupcakes
56 - 17
56 = 40 + 16
17 = 10 + 7
Result: 39 cupcakes