\(67 + 28\)
Carrying (Regrouping): When adding digits in a place value column results in a number 10 or greater, carry the tens digit to the next higher place value
- Align numbers by place value (ones under ones, tens under tens)
- Start adding from the rightmost place (ones)
- If sum ≥ 10, write the ones digit and carry the tens digit to next place
- Continue to the left
Carry 1 to tens place: 7 + 8 = 15
\(7 + 8 = 15\)
Since 15 ≥ 10, write 5 in ones place and carry 1 to tens place
\(6 + 2 + 1\) (carried) = 9
Tens: 9, Ones: 5
\(67 + 28 = 95\)
• Regrouping: When sum ≥ 10, carry the tens digit to next place
• Place value: Each place represents a power of 10
• Addition: Always add digits in the same place value column
\(83 - 27\)
Borrowing (Regrouping): When subtracting, if the top digit is smaller than the bottom digit, borrow 1 from the next higher place value
Borrowed 1 ten → 10 ones: 83 → 7^{13}
\(3 < 7\), so we cannot subtract: 3 - 7
Borrow 1 ten from 8 tens: 8 tens = 7 tens + 1 ten
Add the borrowed 1 ten to ones: 1 ten = 10 ones
New ones: 3 + 10 = 13 ones
\(13 - 7 = 6\)
\(7 - 2 = 5\)
\(83 - 27 = 56\)
• Regrouping: Borrow 1 from higher place value when needed
• Place value: 1 ten = 10 ones, 1 hundred = 10 tens
• Subtraction: Always subtract bottom number from top number
\(486 + 257\)
Multiple regrouping: When adding across multiple place values, carry sequentially from right to left
Carry 1 from ones to tens (6+7=13), then carry 1 from tens to hundreds (8+5+1=14)
\(6 + 7 = 13\)
Write 3 in ones place, carry 1 to tens place
\(8 + 5 + 1\) (carried) = 14
Write 4 in tens place, carry 1 to hundreds place
\(4 + 2 + 1\) (carried) = 7
Hundreds: 7, Tens: 4, Ones: 3
\(486 + 257 = 743\)
• Sequential carrying: Carry from right to left as needed
• Place value relationships: 10 ones = 1 ten, 10 tens = 1 hundred
• Systematic approach: Work from right to left, carrying as needed
Regrouping: The process of converting between place values to enable operations (carrying in addition, borrowing in subtraction)
Carrying: Moving a group of 10 from one place value to the next higher place value in addition
Borrowing: Taking from a higher place value to add to a lower place value in subtraction
Place value: The value of a digit based on its position in the number
- Align numbers: Match digits by place value
- Identify operation: Determine if addition or subtraction
- Start from right: Begin with the ones place
- Check for regrouping: If needed, apply appropriate operation
- Add each place: Continue working left until all places are done
• Regrouping condition: When sum ≥ 10 in addition or top digit < bottom digit in subtraction
• Place value relationships: 10 ones = 1 ten, 10 tens = 1 hundred
• Inclusion rule: Always include carried digit in next place value addition
• Reduction rule: When borrowing, reduce the higher place value by 1
• Verification: Estimate to check if answer is reasonable
\(503 - 187\)
Multiple borrowing: When subtracting across multiple place values, borrow sequentially from left to right
Borrowed 1 hundred → 10 tens → 9 tens + 1 ten → 10 ones
\(3 < 7\), so we cannot subtract: 3 - 7
Tens place has 0, so we cannot borrow directly from tens
Borrow 1 hundred from 5 hundreds: 5 hundreds = 4 hundreds + 1 hundred
Add the borrowed 1 hundred to tens: 1 hundred = 10 tens
New tens: 0 + 10 = 10 tens
Take 1 ten from 10 tens: 10 tens = 9 tens + 1 ten
Add the borrowed 1 ten to ones: 1 ten = 10 ones
New ones: 3 + 10 = 13 ones
Ones: \(13 - 7 = 6\)
Tens: \(9 - 8 = 1\)
Hundreds: \(4 - 1 = 3\)
\(503 - 187 = 316\)
• Sequential borrowing: When lower place has 0, borrow from higher place first
• Place value relationships: 1 hundred = 10 tens, 1 ten = 10 ones
• Systematic approach: Work from right to left, borrowing as needed
\(647 + 285 - 193\)
Mixed operations: Solving problems with both addition and subtraction in sequence, with regrouping
Ones: \(7 + 5 = 12\), write 2, carry 1
Tens: \(4 + 8 + 1\) (carried) = 13, write 3, carry 1
Hundreds: \(6 + 2 + 1\) (carried) = 9
So: \(647 + 285 = 932\)
Ones: \(2 < 3\), so borrow: 2 becomes 12, tens becomes 2
Now: \(12 - 3 = 9\)
Tens: \(2 < 9\), so borrow: 2 becomes 12, hundreds becomes 8
Now: \(12 - 9 = 3\)
Hundreds: \(8 - 1 = 7\)
Hundreds: 7, Tens: 3, Ones: 9
Check: \(739 + 193 = 932\) and \(932 - 285 = 647\) ✓
\(647 + 285 - 193 = 739\)
• Order of operations: Work from left to right when adding and subtracting
• Sequential processing: Complete each operation before moving to the next
• Verification: Check by reversing the operations