Missing numerator problem: A type of equivalent fraction problem where one numerator is unknown, requiring the use of cross multiplication or proportional reasoning to solve.
Note: In equivalent fractions, the relationship between numerators is the same as the relationship between denominators.
- Identify the known fraction and the fraction with the missing value
- Set up the equation using cross multiplication: 3×8 = 4×?
- Solve for the unknown value by dividing both sides by the known denominator
- Verify the solution by checking if the fractions are equivalent
3/4 = ?/8 → 3×8 = 4×?
3×8 = 24
24 = 4×? → ? = 24÷4 = 6
3/4 = 6/8 → Cross multiply: 3×8 = 24 and 4×6 = 24 ✓
The missing numerator is 6, so 3/4 = 6/8.
• Cross multiplication: In equivalent fractions a/b = c/d, a×d = b×c
• Proportional reasoning: Relationship between numerators matches denominators
• Verification: Always check solution by substituting back into original equation
• Practice Tip: Divide the new denominator by the old denominator to find the multiplication factor
- 2/5 = ?/10 → 2×10 = 5×? → ? = 4, so 2/5 = 4/10
- 1/3 = ?/9 → 1×9 = 3×? → ? = 3, so 1/3 = 3/9
- 5/6 = ?/12 → 5×12 = 6×? → ? = 10, so 5/6 = 10/12
- Always cross multiply to find missing values in equivalent fractions
- Check if the denominator was multiplied by a factor, then multiply numerator by same factor
- Verify your answer by confirming the fractions are equivalent
Q: What if I don't want to use cross multiplication?
A: You can find the multiplication factor by dividing the new denominator by the old denominator, then multiply the numerator by the same factor.
Q: How do I check my answer?
A: Substitute your answer back into the original equation and verify using cross multiplication.
Missing denominator problem: A type of equivalent fraction problem where one denominator is unknown, requiring the use of cross multiplication or proportional reasoning to solve.
Note: In equivalent fractions, the relationship between numerators is the same as the relationship between denominators.
- Identify the known fraction and the fraction with the missing value
- Set up the equation using cross multiplication: 2×? = 3×4
- Solve for the unknown value by dividing both sides by the known numerator
- Verify the solution by checking if the fractions are equivalent
2/3 = 4/? → 2×? = 3×4
3×4 = 12
2×? = 12 → ? = 12÷2 = 6
2/3 = 4/6 → Cross multiply: 2×6 = 12 and 3×4 = 12 ✓
The missing denominator is 6, so 2/3 = 4/6.
• Cross multiplication: In equivalent fractions a/b = c/d, a×d = b×c
• Proportional reasoning: Relationship between numerators matches denominators
• Verification: Always check solution by substituting back into original equation
• Practice Tip: Divide the new numerator by the old numerator to find the multiplication factor
- 3/5 = 6/? → 3×? = 5×6 → ? = 10, so 3/5 = 6/10
- 1/4 = 3/? → 1×? = 4×3 → ? = 12, so 1/4 = 3/12
- 4/7 = 8/? → 4×? = 7×8 → ? = 14, so 4/7 = 8/14
- Always cross multiply to find missing values in equivalent fractions
- Check if the numerator was multiplied by a factor, then multiply denominator by same factor
- Verify your answer by confirming the fractions are equivalent
Q: What if I don't want to use cross multiplication?
A: You can find the multiplication factor by dividing the new numerator by the old numerator, then multiply the denominator by the same factor.
Q: How do I check my answer?
A: Substitute your answer back into the original equation and verify using cross multiplication.
Cross multiplication method: A systematic approach to solve equivalent fraction problems by multiplying diagonally across the fractions.
Note: For equivalent fractions a/b = c/d, the cross products a×d and b×c are always equal.
- Set up the equivalent fraction equation
- Apply cross multiplication: multiply numerator of first fraction by denominator of second
- Set this equal to denominator of first fraction times numerator of second
- Solve for the unknown variable
5/6 = ?/18
5 × 18 = 6 × ?
5 × 18 = 90
90 = 6 × ? → ? = 90 ÷ 6 = 15
5/6 = 15/18 → Cross multiply: 5×18 = 90 and 6×15 = 90 ✓
The missing numerator is 15, so 5/6 = 15/18.
• Cross multiplication: In equivalent fractions a/b = c/d, a×d = b×c
• Diagonal multiplication: Multiply across the diagonals of the fractions
• Isolate variable: Divide both sides by the coefficient of the unknown
• Verification: Confirm with cross multiplication after solving
- 3/4 = ?/12 → 3×12 = 4×? → ? = 9, so 3/4 = 9/12
- 2/7 = ?/21 → 2×21 = 7×? → ? = 6, so 2/7 = 6/21
- 4/5 = ?/25 → 4×25 = 5×? → ? = 20, so 4/5 = 20/25
- Cross multiplication is the most reliable method for finding missing values
- Always multiply numerator of first fraction by denominator of second
- Then multiply denominator of first fraction by numerator of second
Q: Does cross multiplication work for all equivalent fraction problems?
A: Yes, it works for any equivalent fraction problem with one unknown value.
Q: Can I use cross multiplication to compare fractions?
A: Yes, cross multiplication is also used to compare fractions to see which is larger.
Advanced missing value problem: A type of equivalent fraction problem where the unknown value requires careful analysis of the relationship between numerators and denominators.
Note: When solving for a missing denominator, analyze how the numerator changed to determine the denominator relationship.
- Identify how the known numerator changed to become the unknown numerator
- Apply the same relationship to the known denominator
- Alternatively, use cross multiplication to solve algebraically
- Verify the solution by confirming the fractions are equivalent
7/? = 21/27 → 7×27 = ?×21
7×27 = 189
189 = ?×21 → ? = 189÷21 = 9
7/9 = 21/27 → Cross multiply: 7×27 = 189 and 9×21 = 189 ✓
The missing denominator is 9, so 7/9 = 21/27.
• Cross multiplication: In equivalent fractions a/b = c/d, a×d = b×c
• Proportional reasoning: Relationship between numerators matches denominators
• Verification: Always check solution by substituting back into original equation
• Alternative method: 21÷7=3, so 27÷3=9 (divide by same factor)
- 5/? = 15/24 → 5×24 = ?×15 → ? = 8, so 5/8 = 15/24
- 2/? = 10/35 → 2×35 = ?×10 → ? = 7, so 2/7 = 10/35
- 3/? = 18/42 → 3×42 = ?×18 → ? = 7, so 3/7 = 18/42
- When the unknown is in the denominator, cross multiply and divide by the numerator
- Alternatively, find the multiplication factor from numerators and apply to denominators
- Check your work by ensuring the fractions are equivalent
Q: What if the numbers are large?
A: Cross multiplication still works, but you may need to simplify fractions first.
Q: Can I solve this by looking at patterns?
A: Yes, if you notice that 21 = 7×3, then the denominator must be 27÷3 = 9.
Multiple missing values problem: A type of equivalent fraction problem where more than one value is unknown in a chain of equivalent fractions.
Note: When solving for multiple missing values, solve one at a time using the known equivalent fraction as a reference.
- Identify the complete fraction to use as a reference
- Solve for the first missing value using cross multiplication
- Use the newly found equivalent fraction to solve for the next missing value
- Verify all fractions are equivalent
4×9 = 6×? → 36 = 6×? → ? = 6
4×? = 6×8 → 4×? = 48 → ? = 12
4/6 = 6/9 = 8/12 → All simplify to 2/3 ✓
The missing values are 6 and 12, so 4/6 = 6/9 = 8/12.
• Chain of equivalence: All fractions in the chain are equal
• Step-by-step solving: Solve one missing value at a time
• Reference fraction: Use a complete fraction to solve for missing values
• Verification: All fractions should simplify to the same value
- 2/3 = ?/6 = 4/? → ? = 4 and ? = 6, so 2/3 = 4/6 = 4/6
- 3/5 = ?/10 = 9/? → ? = 6 and ? = 15, so 3/5 = 6/10 = 9/15
- 1/4 = ?/8 = 3/? → ? = 2 and ? = 12, so 1/4 = 2/8 = 3/12
- Work with one pair of fractions at a time
- Use the fraction with both values known as your reference
- Verify that all fractions in the chain are equivalent
Q: Can I solve multiple missing values at once?
A: It's better to solve one at a time to avoid confusion.
Q: What if I get different answers for the same fraction?
A: Check your work - all fractions in the chain must be equivalent.