Problem B: A rectangle is 8 inches long and 5 inches wide. What is its perimeter?
Problem C: A triangle has sides of 4 ft, 6 ft, and 5 ft. What is its perimeter?
Problem A: P = 4 × side = 4 × 6 = 24 cm
Problem B: P = 2 × (length + width) = 2 × (8 + 5) = 2 × 13 = 26 inches
Problem C: P = side₁ + side₂ + side₃ = 4 + 6 + 5 = 15 ft
- Identify the shape
- Select the appropriate formula
- Substitute values
- Calculate
Problem A: 24 cm | Problem B: 26 inches | Problem C: 15 ft
• Square Perimeter: P = 4 × side
• Rectangle Perimeter: P = 2 × (length + width)
• Triangle Perimeter: P = sum of all sides
Problem B: A square picture frame has sides of 12 inches. What is the total length of the frame?
Problem C: A triangular playground has sides of 20m, 25m, and 15m. What is its perimeter?
Problem A: P = 2 × (15 + 9) = 2 × 24 = 48 feet
Problem B: P = 4 × 12 = 48 inches
Problem C: P = 20 + 25 + 15 = 60 meters
Problem A: 48 feet | Problem B: 48 inches | Problem C: 60 meters
• Real-world Context: Fencing = perimeter of rectangle
• Frame Length: Perimeter of square picture frame
• Units Consistency: Keep all measurements in same unit
Problem B: Tom is building a square sandbox with sides of 8 feet. How much wood does he need for the border?
Problem C: A triangular flower bed has sides of 3m, 4m, and 5m. What is the total length of the border?
Problem A: P = 2 × (10 + 6) = 2 × 16 = 32 inches
Problem B: P = 4 × 8 = 32 feet
Problem C: P = 3 + 4 + 5 = 12 meters
Problem A: 32 inches of ribbon | Problem B: 32 feet of wood | Problem C: 12 meters of border
• Context Recognition: Words like "around," "border," "fence" indicate perimeter
• Unit Matching: Answer in same unit as given measurements
• Real-world Application: Connect math to practical scenarios
Problem B: A square table has sides of 36 inches. What is the perimeter in feet?
Problem C: An equilateral triangle has sides of 10 cm each. What is its perimeter?
Problem A: P = 2 × (25 + 15) = 2 × 40 = 80 yards
Problem B: P = 4 × 36 = 144 inches = 12 feet
Problem C: P = 10 + 10 + 10 = 30 cm
Problem A: 80 yards | Problem B: 12 feet | Problem C: 30 cm
• Unit Conversion: 12 inches = 1 foot
• Equilateral Triangle: All sides equal, so P = 3 × side
• Distance Around: Another way to say "perimeter"
Problem B: A rectangular room is twice as long as it is wide. If the width is 8 feet, what is the perimeter?
Problem C: A triangular banner has sides in the ratio 3:4:5. If the shortest side is 6 inches, what is the perimeter?
Problem A: Square: P = 4 × 7 = 28 cm; Rectangle: P = 2 × (10 + 4) = 28 cm. Both equal.
Problem B: Length = 2 × 8 = 16 ft; P = 2 × (16 + 8) = 48 feet
Problem C: Sides: 6, 8, 10 inches; P = 6 + 8 + 10 = 24 inches
Problem A: Both perimeters are equal | Problem B: 48 feet | Problem C: 24 inches
• Ratio Problems: Scale sides proportionally
• Comparison Problems: Calculate each separately before comparing
• Relationship Problems: Use given relationships to find unknown dimensions
Worksheet 1 Answers: A: 24 cm, B: 26 in, C: 15 ft
Worksheet 2 Answers: A: 48 ft, B: 48 in, C: 60 m
Worksheet 3 Answers: A: 32 in, B: 32 ft, C: 12 m
Worksheet 4 Answers: A: 80 yd, B: 12 ft, C: 30 cm
Worksheet 5 Answers: A: Both equal (28 cm), B: 48 ft, C: 24 in
Instructions: Solve each worksheet by finding the perimeter. Show your work and include units in your answer.
Remember:
- Read the problem carefully
- Identify the shape and its dimensions
- Choose the correct formula
- Substitute the values
- Calculate the perimeter
- Check your answer
Problem 1: A rectangular garden is 12 feet by 8 feet. How much fencing is needed?
Solution: P = 2 × (12 + 8) = 2 × 20 = 40 feet
Problem 2: A square picture frame has sides of 15 inches. What is the perimeter?
Solution: P = 4 × 15 = 60 inches
Problem 1: A rectangular room is 14 feet long and 10 feet wide. If carpet covers the entire floor, what is the perimeter of the room?
Solution: P = 2 × (14 + 10) = 2 × 24 = 48 feet
Problem 2: A square has the same perimeter as a rectangle that is 16 cm by 4 cm. What is the side length of the square?
Solution: Rectangle P = 2 × (16 + 4) = 40 cm; Square side = 40 ÷ 4 = 10 cm
Problem 1: Find the perimeter of a triangle with sides 7 cm, 9 cm, and 11 cm.
Solution: P = 7 + 9 + 11 = 27 cm
Problem 2: A rectangular playground is 20 yards long and 15 yards wide. What is the distance around it?
Solution: P = 2 × (20 + 15) = 70 yards