Mixed Number: A number that combines a whole number and a proper fraction (e.g., 3½, 5¾)
Proper Fraction: A fraction where the numerator is less than the denominator
Improper Fraction: A fraction where the numerator is greater than or equal to the denominator
Borrowing: The process of converting 1 whole unit into fractional parts to enable subtraction
Regrouping: Rearranging mixed numbers to facilitate subtraction operations
Mixed Number: A combination of a whole number and a proper fraction (e.g., 2½)
Proper Fraction: A fraction where the numerator is smaller than the denominator (e.g., 3/4)
Improper Fraction: A fraction where the numerator is greater than or equal to the denominator (e.g., 5/3)
Common Denominator: The same denominator in two or more fractions
Borrowing: Converting 1 whole unit into equivalent fractional parts when the fraction part of the minuend is smaller than the fraction part of the subtrahend
Minuend: The number being subtracted from (the first number in subtraction)
Subtrahend: The number being subtracted (the second number in subtraction)
- Identify the problem: Recognize that you have mixed numbers to subtract
- Check denominators: If different, find LCD and convert fractions
- Compare numerators: If minuend fraction is smaller than subtrahend fraction, borrow from whole number
- Borrow if needed: Convert 1 whole to equivalent fraction and add to existing fraction
- Subtract fractions: Subtract numerators while keeping denominator
- Subtract whole numbers: Subtract whole number parts
- Combine results: Write the answer as a mixed number
- Simplify: Reduce final fraction if possible
• Rule 1: Only subtract fractions when denominators are the same
• Rule 2: When borrowing, convert 1 whole to equivalent fraction: 1 = denominator/denominator
• Rule 3: Always subtract the numerator of the subtrahend from the numerator of the minuend
• Rule 4: Borrow when the fraction part of the minuend is smaller than the fraction part of the subtrahend
• Rule 5: The result should always be smaller than the original number (minuend)
We have mixed numbers with the same denominator (5). We need to subtract both whole numbers and fractions.
Since denominators are the same, subtract whole numbers and fractions separately.
\(\frac{3}{5}\) vs \(\frac{1}{5}\) → \(\frac{3}{5} > \frac{1}{5}\), so no borrowing needed
\(\frac{3}{5} - \frac{1}{5} = \frac{3-1}{5} = \frac{2}{5}\)
4 - 2 = 2
2 + \(\frac{2}{5}\) = 2\(\frac{2}{5}\)
\(\frac{2}{5}\) is already in simplest form
\(4\frac{3}{5} - 2\frac{1}{5} = 2\frac{2}{5}\)
We have mixed numbers with the same denominator (4). Since \(\frac{1}{4} < \frac{3}{4}\), we need to borrow from the whole number.
\(\frac{1}{4}\) vs \(\frac{3}{4}\) → \(\frac{1}{4} < \frac{3}{4}\), so borrowing is needed
Take 1 from 6: 6 - 1 = 5
Convert 1 to fourths: 1 = \(\frac{4}{4}\)
New mixed number: 5 + \(\frac{4}{4} + \frac{1}{4} = 5\frac{5}{4}\)
\(5\frac{5}{4} - 3\frac{3}{4}\)
\(\frac{5}{4} - \frac{3}{4} = \frac{5-3}{4} = \frac{2}{4}\)
5 - 3 = 2
2 + \(\frac{2}{4}\) = 2\(\frac{2}{4}\)
\(\frac{2}{4} = \frac{1}{2}\)
So the answer is 2\(\frac{1}{2}\)
\(6\frac{1}{4} - 3\frac{3}{4} = 2\frac{1}{2}\)
We have mixed numbers with different denominators (2 and 3). First, find LCD and convert fractions.
Denominators: 2 and 3
Multiples of 2: 2, 4, 6, 8...
Multiples of 3: 3, 6, 9...
LCD = 6
\(7\frac{1}{2} = 7\frac{3}{6}\) (multiply numerator and denominator by 3)
\(3\frac{1}{3} = 3\frac{2}{6}\) (multiply numerator and denominator by 2)
\(7\frac{3}{6} - 3\frac{2}{6}\)
\(\frac{3}{6}\) vs \(\frac{2}{6}\) → \(\frac{3}{6} > \frac{2}{6}\), so no borrowing needed
\(\frac{3}{6} - \frac{2}{6} = \frac{3-2}{6} = \frac{1}{6}\)
7 - 3 = 4
4 + \(\frac{1}{6}\) = 4\(\frac{1}{6}\)
\(7\frac{1}{2} - 3\frac{1}{3} = 4\frac{1}{6}\)
We have mixed numbers with the same denominator (7). Since \(\frac{2}{7} < \frac{5}{7}\), we need to borrow from the whole number.
\(\frac{2}{7}\) vs \(\frac{5}{7}\) → \(\frac{2}{7} < \frac{5}{7}\), so borrowing is needed
Take 1 from 9: 9 - 1 = 8
Convert 1 to sevenths: 1 = \(\frac{7}{7}\)
New mixed number: 8 + \(\frac{7}{7} + \frac{2}{7} = 8\frac{9}{7}\)
\(8\frac{9}{7} - 5\frac{5}{7}\)
\(\frac{9}{7} - \frac{5}{7} = \frac{9-5}{7} = \frac{4}{7}\)
8 - 5 = 3
3 + \(\frac{4}{7}\) = 3\(\frac{4}{7}\)
\(\frac{4}{7}\) is already in simplest form
\(9\frac{2}{7} - 5\frac{5}{7} = 3\frac{4}{7}\)
We have mixed numbers with different denominators (4 and 3). Need to find LCD and may need to borrow.
Denominators: 4 and 3
Prime factors of 4: \(2^2\)
Prime factors of 3: 3
LCD = \(2^2 \times 3 = 12\)
\(10\frac{1}{4} = 10\frac{3}{12}\) (multiply numerator and denominator by 3)
\(6\frac{2}{3} = 6\frac{8}{12}\) (multiply numerator and denominator by 4)
\(10\frac{3}{12} - 6\frac{8}{12}\)
\(\frac{3}{12}\) vs \(\frac{8}{12}\) → \(\frac{3}{12} < \frac{8}{12}\), so borrowing is needed
Take 1 from 10: 10 - 1 = 9
Convert 1 to twelfths: 1 = \(\frac{12}{12}\)
New mixed number: 9 + \(\frac{12}{12} + \frac{3}{12} = 9\frac{15}{12}\)
\(9\frac{15}{12} - 6\frac{8}{12}\)
\(\frac{15}{12} - \frac{8}{12} = \frac{15-8}{12} = \frac{7}{12}\)
9 - 6 = 3
3 + \(\frac{7}{12}\) = 3\(\frac{7}{12}\)
GCF of 7 and 12 is 1, so \(\frac{7}{12}\) is already in simplest form
\(10\frac{1}{4} - 6\frac{2}{3} = 3\frac{7}{12}\)