- Grade Level: 4th Grade
- Subject: Mathematics
- Topic: Division with Remainders
- Number of Problems: 30
- Difficulty: Progressive (Easy to Hard)
Dividend: The number being divided (the total amount)
Divisor: The number by which we divide (the group size)
Quotient: The result of division (number of complete groups)
Remainder: What's left over after division (leftover items)
Division Algorithm: The fundamental relationship: Dividend = Divisor × Quotient + Remainder
- Easy Problems (1-10): 2-digit dividends ÷ 1-digit divisors
- Medium Problems (11-20): 2-digit dividends ÷ 1-digit divisors
- Hard Problems (21-30): 3-digit dividends ÷ 1-digit divisors
| Problem # | Division Problem | Your Answer |
|---|---|---|
| 1 | 13 ÷ 4 | |
| 2 | 23 ÷ 5 | |
| 3 | 37 ÷ 6 | |
| 4 | 45 ÷ 7 | |
| 5 | 58 ÷ 8 | |
| 6 | 67 ÷ 9 | |
| 7 | 73 ÷ 6 | |
| 8 | 84 ÷ 7 | |
| 9 | 92 ÷ 8 | |
| 10 | 103 ÷ 9 | |
| 11 | 123 ÷ 5 | |
| 12 | 147 ÷ 6 | |
| 13 | 164 ÷ 7 | |
| 14 | 183 ÷ 8 | |
| 15 | 204 ÷ 9 |
Dividend = 23, Divisor = 5
How many times does 5 fit in 23? 5 × 4 = 20, 5 × 5 = 25 (too big)
5 × 4 = 20
23 - 20 = 3
3 < 5 ✓
5 × 4 + 3 = 20 + 3 = 23 ✓
- Forgetting to check if remainder is smaller than divisor
- Miscalculating multiplication facts during division
- Confusing quotient with remainder in the final answer
- Not verifying answers using the division algorithm