Instructions:
Solve each problem below. Show your work using the division algorithm: Dividend = (Divisor × Quotient) + Remainder. Write your answer as "quotient R remainder".
4 × 6 = 24
25 - 24 = 1
So 25 ÷ 4 = 6 R 1
(4 × 6) + 1 = 24 + 1 = 25 ✓
6 × 6 = 36
38 - 36 = 2
So 38 ÷ 6 = 6 R 2
(6 × 6) + 2 = 36 + 2 = 38 ✓
8 × 7 = 56
57 - 56 = 1
So 57 ÷ 8 = 7 R 1
(8 × 7) + 1 = 56 + 1 = 57 ✓
9 × 8 = 72
73 - 72 = 1
So 73 ÷ 9 = 8 R 1
(9 × 8) + 1 = 72 + 1 = 73 ✓
Division with Remainders Practice Worksheet for 4th Grade Students
Comprehensive worksheet with 10 challenging practice problems on division with remainders: long division, word problems, and verification exercises.
Instructions:
Solve each problem below. Show your work using long division method. Write your answer as "quotient R remainder". Verify your answer using: Dividend = (Divisor × Quotient) + Remainder
Step 1: 6 goes into 8 once (6 × 1 = 6)
Step 2: 8 - 6 = 2, bring down 4 to make 24
Step 3: 6 goes into 24 four times (6 × 4 = 24)
Step 4: 24 - 24 = 0
So 84 ÷ 6 = 14 R 0
(6 × 14) + 0 = 84 + 0 = 84 ✓
Step 1: 8 goes into 9 once (8 × 1 = 8)
Step 2: 9 - 8 = 1, bring down 7 to make 17
Step 3: 8 goes into 17 twice (8 × 2 = 16)
Step 4: 17 - 16 = 1
So 97 ÷ 8 = 12 R 1
(8 × 12) + 1 = 96 + 1 = 97 ✓
Step 1: 9 goes into 12 once (9 × 1 = 9)
Step 2: 12 - 9 = 3, bring down 3 to make 33
Step 3: 9 goes into 33 three times (9 × 3 = 27)
Step 4: 33 - 27 = 6
So 123 ÷ 9 = 13 R 6
(9 × 13) + 6 = 117 + 6 = 123 ✓
Step 1: 7 goes into 15 twice (7 × 2 = 14)
Step 2: 15 - 14 = 1, bring down 8 to make 18
Step 3: 7 goes into 18 twice (7 × 2 = 14)
Step 4: 18 - 14 = 4
So 158 ÷ 7 = 22 R 4
(7 × 22) + 4 = 154 + 4 = 158 ✓
145 ÷ 12 = ?
12 × 12 = 144
145 - 144 = 1
So 12 buses are filled completely, and 1 student needs an additional bus
Therefore, 13 buses are needed, with 1 student on the last bus
(12 × 12) + 1 = 144 + 1 = 145 ✓
89 ÷ 8 = ?
8 × 11 = 88
89 - 88 = 1
So 11 full shelves can be filled with 1 book left over
(8 × 11) + 1 = 88 + 1 = 89 ✓
247 ÷ 6 = ?
6 × 41 = 246
247 - 246 = 1
So 41 full boxes can be made with 1 car left unpacked
(6 × 41) + 1 = 246 + 1 = 247 ✓
183 ÷ 7 = ?
7 × 26 = 182
183 - 182 = 1
So 26 complete sets can be made with 1 pencil left over
(7 × 26) + 1 = 182 + 1 = 183 ✓
317 ÷ 15 = ?
15 × 21 = 315
317 - 315 = 2
So 21 full groups can be formed with 2 campers left over
(15 × 21) + 2 = 315 + 2 = 317 ✓
483 ÷ 18 = ?
18 × 26 = 468
483 - 468 = 15
So 26 trips with full loads, and 1 trip with 15 packages
Therefore, 27 trips total, with 15 packages on the final trip
(18 × 26) + 15 = 468 + 15 = 483 ✓
(11 × 12) + 5 = 132 + 5 = 137 ✓
Questions & Answers
Question: I'm having trouble with long division. How do I know when to stop bringing down numbers?
Answer: Great question! You stop bringing down numbers when:
- You've brought down all the digits from the dividend
- The number you're working with is smaller than the divisor
- There are no more digits to bring down
Once you reach this point, whatever number is left becomes your remainder. Remember the acronym: DMSB (Divide, Multiply, Subtract, Bring down).
Question: How can I help my child practice division with remainders effectively?
Answer: Here are effective strategies:
- Start with concrete examples: Use physical objects like blocks or counters
- Practice basic facts: Strengthen multiplication facts to support division
- Use graph paper: Helps keep long division organized
- Check answers together: Reinforce the verification process
- Connect to real life: Use word problems that relate to daily activities
Consistent practice with immediate feedback works best!
Question: How do I know if my remainder is correct? Sometimes I get confused about whether it's too big.
Answer: There's a simple rule to check:
- The remainder must always be smaller than the divisor
- If your remainder is equal to or bigger than the divisor, you made a mistake
- Always check: (Divisor × Quotient) + Remainder = Original Dividend
Example: In 23 ÷ 5 = 4 R 3, check that 3 < 5 ✓
Then verify: (5 × 4) + 3 = 20 + 3 = 23 ✓