Level 1: Basic equivalent fractions (simple denominators)
Level 2: Finding missing numerators/denominators
Level 3: Simplifying fractions to lowest terms
Level 4: Complex equivalent fractions (large numbers)
Level 5: Mixed practice and word problems
Current Progress: 75%
Completed: 15/20 exercises
• Multiplication Property: \(\frac{a}{b} = \frac{a \times n}{b \times n}\) where \(n \neq 0\)
• Division Property: \(\frac{a}{b} = \frac{a \div n}{b \div n}\) where \(n \neq 0\)
• Cross Product Rule: \(\frac{a}{b} = \frac{c}{d}\) if \(ad = bc\)
\(\frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6}\)
\(\frac{2}{3} = \frac{2 \times 3}{3 \times 3} = \frac{6}{9}\)
\(\frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12}\)
From 5 to 20: \(5 \times 4 = 20\)
Apply to numerator: \(3 \times 4 = 12\)
Verification: \(3 \times 20 = 60\) and \(5 \times 12 = 60\) ✓
Factors of 18: 1, 2, 3, 6, 9, 18
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
GCF = 6
\(\frac{18 \div 6}{24 \div 6} = \frac{3}{4}\)
\(\frac{35}{49}\): GCF(35,49) = 7, so \(\frac{35 \div 7}{49 \div 7} = \frac{5}{7}\)
\(\frac{45}{63}\): GCF(45,63) = 9, so \(\frac{45 \div 9}{63 \div 9} = \frac{5}{7}\)
Both simplify to \(\frac{5}{7}\), so they are equivalent.
\(35 \times 63 = 2205\) and \(49 \times 45 = 2205\)
Since both products equal 2205, the fractions are equivalent.
Numerators: 2, 4, 6, 8, 10, 12 (multiply by 1, 2, 3, 4, 5, 6)
Denominators: 3, 6, 9, 12, 15, 18 (multiply by 1, 2, 3, 4, 5, 6)
Each fraction is equivalent to \(\frac{2}{3}\) multiplied by the sequence number.
Find the relationship: \(\frac{8}{12} = \frac{2}{3}\)
Scale the flour: \(\frac{3}{4} \times \frac{3}{2} = \frac{9}{8} = 1\frac{1}{8}\) cups
Alternatively: \(\frac{3}{4} \times 12 \div 8 = \frac{36}{32} = \frac{9}{8}\)