Equivalent Fractions: Fractions that represent the same value or portion of a whole.
Numerator: The top number in a fraction, showing how many parts are taken.
Denominator: The bottom number in a fraction, showing the total number of equal parts.
Greatest Common Factor (GCF): The largest number that divides evenly into two or more numbers.
Category 1: Basic equivalent fraction creation
Category 2: Finding missing numerators or denominators
Category 3: Simplifying fractions to lowest terms
Category 4: Verifying equivalence using cross multiplication
Category 5: Complex equivalent fractions with large numbers
Category 6: Real-world applications and word problems
• Multiplication Property: \(\frac{a}{b} = \frac{a \times n}{b \times n}\) where \(n \neq 0\)
• Division Property: \(\frac{a}{b} = \frac{a \div n}{b \div n}\) where \(n \neq 0\)
• Cross Product Rule: \(\frac{a}{b} = \frac{c}{d}\) if \(ad = bc\)
• Simplification Rule: Divide numerator and denominator by their GCF to get lowest terms.
This is a basic question focusing on the multiplication property of equivalent fractions.
1. Original fraction: \(\frac{1}{2}\)
2. Multiply both by 3: \(\frac{1 \times 3}{2 \times 3} = \frac{3}{6}\)
3. Verification: \(1 \times 6 = 6\) and \(2 \times 3 = 6\) ✓
This question tests the ability to find missing values in equivalent fraction equations.
1. Analyze denominators: \(3 \times 3 = 9\)
2. Apply same factor to numerator: \(2 \times 3 = 6\)
3. Verification: \(2 \times 9 = 18\) and \(3 \times 6 = 18\) ✓
This question focuses on basic simplification using common factors.
1. Find GCF of 4 and 8: GCF = 4
2. Divide both by 4: \(\frac{4 \div 4}{8 \div 4} = \frac{1}{2}\)
3. Verification: \(4 \times 2 = 8\) and \(8 \times 1 = 8\) ✓
This question requires multiple verification methods and higher-level thinking.
\(\frac{15}{25}\): GCF(15,25) = 5, so \(\frac{15 \div 5}{25 \div 5} = \frac{3}{5}\)
\(\frac{21}{35}\): GCF(21,35) = 7, so \(\frac{21 \div 7}{35 \div 7} = \frac{3}{5}\)
Both equal \(\frac{3}{5}\), so they are equivalent.
\(15 \times 35 = 525\) and \(25 \times 21 = 525\) ✓
This question tests pattern recognition and sequence continuation skills.
Numerators: 1, 2, 3, 4, 5 (counting by 1)
Denominators: 4, 8, 12, 16, 20 (multiples of 4)
Each fraction equals \(\frac{1}{4}\) multiplied by 1, 2, 3, 4, 5 respectively.
This question applies equivalent fractions to real-world scenarios.
1. Find the scaling factor: \(18 \div 6 = 3\)
2. Scale the sugar: \(\frac{3}{4} \times 3 = \frac{9}{4}\)
3. Convert to mixed number: \(\frac{9}{4} = 2\frac{1}{4}\) cups
4. Verification: \(3 \times 4 = 12\) and \(4 \times 3 = 12\) ✓