Simplifying fractions: Reducing a fraction to its lowest terms by dividing both numerator and denominator by their Greatest Common Divisor (GCD)
- Find factors of numerator (15): 1, 3, 5, 15
- Find factors of denominator (25): 1, 5, 25
- Identify the Greatest Common Divisor: 5
- Divide both numerator and denominator by GCD
15 = 1 × 15, 3 × 5
Factors of 15: 1, 3, 5, 15
25 = 1 × 25, 5 × 5
Factors of 25: 1, 5, 25
Common factors: 1, 5
Greatest Common Divisor: 5
\(\frac{15}{25} = \frac{15 ÷ 5}{25 ÷ 5} = \frac{3}{5}\)
\(\frac{15}{25} = \frac{3}{5}\)
• GCD Method: Divide both numerator and denominator by their greatest common divisor
• Equivalence: The value of the fraction remains unchanged
• Lowest Terms: A fraction is in lowest terms when GCD of numerator and denominator is 1
Prime factorization: Breaking down numbers into their prime factors to identify common factors
28 = 2 × 14 = 2 × 2 × 7 = \(2^2 × 7\)
42 = 2 × 21 = 2 × 3 × 7
\(\frac{2^2 × 7}{2 × 3 × 7} = \frac{2^{2-1} × 7^{1-1}}{3} = \frac{2}{3}\)
\(\frac{2}{3}\) cannot be simplified further since GCD(2,3) = 1
\(\frac{28}{42} = \frac{2}{3}\)
• Prime Factorization: Express numbers as products of prime factors
• Canceling Common Factors: Remove identical factors from numerator and denominator
• Lowest Terms: Result is in lowest terms when no common factors remain
Euclidean Algorithm: An efficient method to find GCD of large numbers by repeated division
\(75 ÷ 45 = 1\) remainder \(30\)
\(45 ÷ 30 = 1\) remainder \(15\)
\(30 ÷ 15 = 2\) remainder \(0\)
So GCD(45,75) = 15
\(\frac{45}{75} = \frac{45 ÷ 15}{75 ÷ 15} = \frac{3}{5}\)
\(3 × 75 = 225\) and \(5 × 45 = 225\), so cross products are equal
GCD(3,5) = 1, so \(\frac{3}{5}\) is in lowest terms
\(\frac{45}{75} = \frac{3}{5}\)
• Euclidean Algorithm: Efficient GCD calculation for large numbers
• Cross Multiplication: Verification method for equivalent fractions
• Lowest Terms Verification: GCD of numerator and denominator equals 1
Numerator: Top number in a fraction (the dividend)
Denominator: Bottom number in a fraction (the divisor)
Greatest Common Divisor (GCD): Largest number that divides both numerator and denominator evenly
Equivalent Fractions: Fractions that represent the same value but have different numerators and denominators
Lowest Terms: A fraction is in lowest terms when the only common factor of numerator and denominator is 1
- Identify the fraction: Recognize the numerator and denominator
- Find GCD: Use factor listing, prime factorization, or Euclidean algorithm
- Divide both parts: Divide numerator and denominator by GCD
- Verify result: Check that GCD of new numerator and denominator is 1
- Check equivalence: Use cross multiplication to confirm
• Basic Simplification: \(\frac{a}{b} = \frac{a ÷ \gcd(a,b)}{b ÷ \gcd(a,b)}\)
• Verification: Two fractions \(\frac{a}{b}\) and \(\frac{c}{d}\) are equivalent if \(a×d = b×c\)
• Lowest Terms: A fraction \(\frac{a}{b}\) is in lowest terms if \(\gcd(a,b) = 1\)
• Prime Factorization: Cancel identical prime factors from numerator and denominator
• Euclidean Algorithm: For finding GCD of large numbers efficiently
Fraction Simplification Infographic
Represents 15 parts out of 25 total parts
GCD of numerator and denominator = 1
\(\gcd(3,5) = 1\)
Therefore \(\frac{3}{5}\) is in lowest terms
- Only dividing the numerator
- Not checking if result is in lowest terms
- Missing common factors
- Arithmetic errors in division
- Stopping before full simplification
Multiple simplification steps: Some fractions require multiple rounds of division before reaching lowest terms
Both 56 and 84 are divisible by 2
\(\frac{56}{84} = \frac{56 ÷ 2}{84 ÷ 2} = \frac{28}{42}\)
Both 28 and 42 are divisible by 14
\(\frac{28}{42} = \frac{28 ÷ 14}{42 ÷ 14} = \frac{2}{3}\)
Factors of 2: 1, 2
Factors of 3: 1, 3
Common factor: 1, so \(\frac{2}{3}\) is in lowest terms
GCD(56,84) = 28
\(\frac{56}{84} = \frac{56 ÷ 28}{84 ÷ 28} = \frac{2}{3}\)
\(\frac{56}{84} = \frac{2}{3}\)
• Progressive Simplification: Multiple division steps if needed
• Direct GCD Method: Single-step approach using greatest common divisor
• Verification: Confirm final fraction has GCD of 1
Real-world fractions: Represent ratios of quantities in practical scenarios
Slices eaten = 24
Total slices = 36
Fraction eaten = \(\frac{24}{36}\)
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
GCD = 12
\(\frac{24}{36} = \frac{24 ÷ 12}{36 ÷ 12} = \frac{2}{3}\)
\(\frac{2}{3}\) of the pizza was eaten
This means 2 out of every 3 slices were eaten
\(\frac{2}{3}\) of the pizza was eaten
• Fraction Setup: Numerator = part, Denominator = whole
• Real-world Context: Interpret mathematical results in practical terms
• Simplification: Always reduce to lowest terms for clarity