Arithmetic sequence: A sequence where each term increases by a constant difference
- Find the difference between consecutive terms
- Check if the difference is constant
- If constant, the sequence is arithmetic
12 - 7 = 5
17 - 12 = 5
22 - 17 = 5
27 - 22 = 5
All differences equal 5, so the sequence is arithmetic
The common difference (d) is 5
Yes, this is an arithmetic sequence with a common difference of 5
• Arithmetic Test: If differences between consecutive terms are constant, it's arithmetic
• Common Difference: The constant value added to each term
• Verification: Check multiple pairs to ensure consistency
Missing terms: Unknown values in a sequence that maintain the arithmetic pattern
From 11 to 15: 15 - 11 = 4
From 15 to 23: 23 - 15 = 8, but this spans 2 positions, so 8 ÷ 2 = 4 per step
After 3: 3 + 4 = 7
After 15: 15 + 4 = 19
3, 7, 11, 15, 19, 23 (each difference is 4) ✓
The missing terms are 7 and 19
• Consistent Difference: The common difference must be the same throughout
• Sequential Addition: Add the common difference to find next terms
• Verification: Check that all differences equal the common difference
nth term: A formula that allows finding any term in a sequence without listing all previous terms
First term (a₁) = 8
Common difference (d) = 13 - 8 = 5
Formula: aₙ = a₁ + (n-1)d
aₙ = 8 + (n-1)5
a₁₂ = 8 + (12-1)5
a₁₂ = 8 + 11×5
a₁₂ = 8 + 55 = 63
Check: 8, 13, 18, 23, 28, 33, 38, 43, 48, 53, 58, 63 (each adds 5) ✓
The 12th term of the sequence is 63
• Arithmetic Formula: aₙ = a₁ + (n-1)d
• Substitution: Replace variables with known values
• Order of Operations: Calculate (n-1) first, then multiply by d
Arithmetic Sequence: A sequence where each term increases by a constant difference
Common Difference (d): The constant value added to each term to get the next term
First Term (a₁): The initial value in the sequence
nth Term (aₙ): The term at position n in the sequence
Consecutive Terms: Terms that follow one after another in the sequence
Finite Sequence: Has a limited number of terms
Infinite Sequence: Continues indefinitely
- Identify the sequence type: Check if differences between terms are constant
- Find the common difference: Subtract consecutive terms
- Use the appropriate formula: For nth term, sum, or missing terms
- Substitute known values: Replace variables in the formula
- Calculate: Perform the mathematical operations
- Verify: Check that your answer makes sense in the context
• nth term: \(a_n = a_1 + (n-1)d\)
• Sum of n terms: \(S_n = \frac{n}{2}(a_1 + a_n)\)
• Common difference: \(d = a_{n+1} - a_n\)
• Alternative sum: \(S_n = \frac{n}{2}[2a_1 + (n-1)d]\)
Decreasing arithmetic sequence: An arithmetic sequence with a negative common difference
43 - 50 = -7
36 - 43 = -7
29 - 36 = -7
Common difference (d) = -7
First term (a₁) = 50
Formula: aₙ = a₁ + (n-1)d
aₙ = 50 + (n-1)(-7)
Substitute n = 8: a₈ = 50 + (8-1)(-7)
a₈ = 50 + 7×(-7)
a₈ = 50 - 49 = 1
The 8th term of the sequence is 1
• Negative Common Difference: Results in a decreasing sequence
• Same Formula: Arithmetic formula works for both increasing and decreasing sequences
• Sign Matters: Negative differences are subtracted in calculations
Sum of arithmetic sequence: The total of all terms in the sequence up to a certain position
First term (a₁) = 6
Common difference (d) = 10 - 6 = 4
Number of terms (n) = 10
aₙ = a₁ + (n-1)d
a₁₀ = 6 + (10-1)4 = 6 + 36 = 42
Formula: Sₙ = n/2(a₁ + aₙ)
S₁₀ = 10/2(6 + 42) = 5 × 48 = 240
Formula: Sₙ = n/2[2a₁ + (n-1)d]
S₁₀ = 10/2[2(6) + (10-1)4] = 5[12 + 36] = 5 × 48 = 240 ✓
The sum of the first 10 terms is 240
• Sum Formula: Sₙ = n/2(a₁ + aₙ) or Sₙ = n/2[2a₁ + (n-1)d]
• Two Options: Use either formula depending on available information
• Verification: Both formulas should yield the same result
Arithmetic Sequence: A sequence where each term increases by a constant difference (d)
Common Difference (d): The fixed number added to each term to get the next term
First Term (a₁): The initial value in the sequence
nth Term (aₙ): The term at position n in the sequence
Increasing Sequence: When d > 0 (positive common difference)
Decreasing Sequence: When d < 0 (negative common difference)
Finite Sequence: Has a limited number of terms
Infinite Sequence: Continues indefinitely
- Identify the sequence: Check if differences between consecutive terms are constant
- Find the common difference: Calculate d = a₂ - a₁
- Determine what's needed: nth term, sum, or missing terms
- Select the appropriate formula: Use the correct formula for the task
- Substitute values: Replace variables with known quantities
- Calculate: Perform the mathematical operations carefully
- Verify: Check that your answer makes sense in the sequence context
• nth term: \(a_n = a_1 + (n-1)d\)
• Sum of n terms: \(S_n = \frac{n}{2}(a_1 + a_n)\)
• Common difference: \(d = a_{n+1} - a_n\)
• Alternative sum: \(S_n = \frac{n}{2}[2a_1 + (n-1)d]\)
• Middle term (for odd n): \(\frac{a_1 + a_n}{2}\)
\(f_1(n) = 3n + 2\) (increasing)
\(f_2(n) = 50 - 4n\) (decreasing)
\(f_3(n) = 10 + 0n\) (constant)
Analysis: The chart shows how different arithmetic sequences behave.
- \(f_1(n) = 3n + 2\): Increasing sequence (positive slope)
- \(f_2(n) = 50 - 4n\): Decreasing sequence (negative slope)
- \(f_3(n) = 10\): Constant sequence (zero slope)