Multiplying Fractions by Fractions Worksheet with Answers - Grade 4

Complete worksheet with answers for multiplying fractions by fractions: comprehensive examples, step-by-step solutions, visual representations, and key strategies for Grade 4 students.

Worksheet Problems 1 to 3 with Answers
1 Basic fraction multiplication
Problem 1
Multiply: \(\frac{2}{3} \times \frac{4}{5}\)
Definition:

Fraction multiplication: Multiply numerators together and denominators together

Solution method:
  1. Multiply the numerators: \(2 \times 4 = 8\)
  2. Multiply the denominators: \(3 \times 5 = 15\)
  3. Write the result: \(\frac{8}{15}\)
Expression
\(\frac{2}{3} \times \frac{4}{5}\)
Multiplication
\(\frac{8}{15}\)
Step 1: Identify the numerators

First fraction: numerator is 2

Second fraction: numerator is 4

Step 2: Multiply the numerators

\(2 \times 4 = 8\)

Step 3: Identify the denominators

First fraction: denominator is 3

Second fraction: denominator is 5

Step 4: Multiply the denominators

\(3 \times 5 = 15\)

Step 5: Write the result

\(\frac{2}{3} \times \frac{4}{5} = \frac{8}{15}\)

\(\frac{2}{3} \times \frac{4}{5} = \frac{8}{15}\)
Final answer:

\(\frac{2}{3} \times \frac{4}{5} = \frac{8}{15}\)

Applied rules:

• Numerator multiplication: \(2 \times 4 = 8\)

• Denominator multiplication: \(3 \times 5 = 15\)

• General rule: \(\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\)

2 Multiplication with simplification
Problem 2
Multiply and simplify: \(\frac{3}{4} \times \frac{2}{6}\)
Definition:

Fraction simplification: Reduce by dividing numerator and denominator by their GCD

Expression
\(\frac{3}{4} \times \frac{2}{6}\)
Multiplication
\(\frac{6}{24}\)
Simplification
\(\frac{1}{4}\)
Step 1: Multiply numerators

\(3 \times 2 = 6\)

Step 2: Multiply denominators

\(4 \times 6 = 24\)

Step 3: Write the result

\(\frac{3}{4} \times \frac{2}{6} = \frac{6}{24}\)

Step 4: Find GCD of 6 and 24

Factors of 6: 1, 2, 3, 6

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

GCD(6, 24) = 6

Step 5: Simplify the fraction

\(\frac{6 \div 6}{24 \div 6} = \frac{1}{4}\)

\(\frac{3}{4} \times \frac{2}{6} = \frac{1}{4}\)
Final answer:

\(\frac{3}{4} \times \frac{2}{6} = \frac{1}{4}\)

Applied rules:

• Multiplication: Numerator × numerator over denominator × denominator

• Simplification: Divide by greatest common divisor

• Reduction: Always express fractions in simplest form

3 Cross-cancellation example
Problem 3
Multiply and simplify: \(\frac{4}{9} \times \frac{3}{8}\)
Definition:

Cross-cancellation: Cancel common factors before multiplication

Expression
\(\frac{4}{9} \times \frac{3}{8}\)
Cross-cancellation
\(\frac{1}{3} \times \frac{1}{2}\)
Result
\(\frac{1}{6}\)
Step 1: Look for cross-cancellation opportunities

Numerator 4 and denominator 8 share factor 4

Numerator 3 and denominator 9 share factor 3

Step 2: Apply cross-cancellation

\(\frac{4}{9} \times \frac{3}{8} = \frac{4 \div 4}{9 \div 3} \times \frac{3 \div 3}{8 \div 4} = \frac{1}{3} \times \frac{1}{2}\)

Step 3: Multiply simplified fractions

\(\frac{1}{3} \times \frac{1}{2} = \frac{1 \times 1}{3 \times 2} = \frac{1}{6}\)

Step 4: Verify result

Original method: \(\frac{4 \times 3}{9 \times 8} = \frac{12}{72} = \frac{1}{6}\) ✓

\(\frac{4}{9} \times \frac{3}{8} = \frac{1}{6}\)
Final answer:

\(\frac{4}{9} \times \frac{3}{8} = \frac{1}{6}\)

Applied rules:

• Cross-cancellation: Cancel common factors before multiplying

• Simplification: Makes calculations easier

• Verification: Check result using original method

Worksheet Guide: Rules and Methods
\(\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}\)
Basic Rule
Rule 1
\(\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\)
Multiply numerators and denominators
Rule 2
Cross-cancellation
Cancel before multiplying
Rule 3
Simplification
Reduce to lowest terms
Key definitions:

Numerator: Top number in a fraction representing parts taken

Denominator: Bottom number in a fraction representing total equal parts

Cross-cancellation: Canceling common factors before multiplication

Simplification: Reducing fraction to lowest terms using GCD

GCD: Greatest Common Divisor - largest number that divides both numbers

Complete methodology:
  1. Look for common factors: Check if any numerator and denominator share factors
  2. Cross-cancel if possible: Divide both by their GCD before multiplying
  3. Multiply numerators: Multiply all top numbers together
  4. Multiply denominators: Multiply all bottom numbers together
  5. Simplify: Reduce to lowest terms if possible
Tip 1: Always cross-cancel first to make multiplication easier.
Tip 2: Remember "top × top, bottom × bottom".
Tip 3: When multiplying by a whole number, put it over 1.
Tip 4: Cross-cancellation prevents having to simplify at the end.
Common errors: Adding instead of multiplying, forgetting to simplify, not cross-cancelling when possible.
Memory aids: "Multiply straight across" - always multiply across, not up and down.
Essential formulas:

• Basic multiplication: \(\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\)

• Whole number × fraction: \(n \times \frac{a}{b} = \frac{na}{b}\)

• Cross-cancellation: Cancel common factors diagonally before multiplying

• Simplification: \(\frac{a}{b} = \frac{a \div \text{GCD}(a,b)}{b \div \text{GCD}(a,b)}\)

Worksheet Problems 4 to 5 with Answers
4 Advanced cross-cancellation
Problem 4
Multiply and simplify: \(\frac{6}{7} \times \frac{14}{9}\)
Definition:

Advanced cross-cancellation: Cancel largest common factors first

Expression
\(\frac{6}{7} \times \frac{14}{9}\)
Cross-cancellation
\(\frac{2}{1} \times \frac{2}{3}\)
Result
\(\frac{4}{3}\)
Step 1: Identify cross-cancellation opportunities

Numerator 6 and denominator 9 share factor 3: \(\frac{6}{9} = \frac{2}{3}\)

Numerator 14 and denominator 7 share factor 7: \(\frac{14}{7} = \frac{2}{1}\)

Step 2: Apply cross-cancellation

\(\frac{6}{7} \times \frac{14}{9} = \frac{6 \div 3}{7 \div 7} \times \frac{14 \div 7}{9 \div 3} = \frac{2}{1} \times \frac{2}{3}\)

Step 3: Multiply simplified fractions

\(\frac{2}{1} \times \frac{2}{3} = \frac{2 \times 2}{1 \times 3} = \frac{4}{3}\)

Step 4: Check for further simplification

GCD(4, 3) = 1, so \(\frac{4}{3}\) is in simplest form

\(\frac{6}{7} \times \frac{14}{9} = \frac{4}{3}\)
Final answer:

\(\frac{6}{7} \times \frac{14}{9} = \frac{4}{3}\)

Applied rules:

• Advanced cross-cancellation: Find largest common factors first

• Simplification: Makes complex multiplication manageable

5 Multiple fraction multiplication
Problem 5
Multiply and simplify: \(\frac{2}{3} \times \frac{5}{4} \times \frac{6}{10}\)
Definition:

Multiple fraction multiplication: Multiply all numerators together and all denominators together

Expression
\(\frac{2}{3} \times \frac{5}{4} \times \frac{6}{10}\)
Cross-cancel
\(\frac{1}{1} \times \frac{1}{2} \times \frac{1}{1}\)
Result
\(\frac{1}{2}\)
Step 1: Look for cross-cancellation opportunities

Numerator 2 and denominator 4 share factor 2: \(\frac{2}{4} = \frac{1}{2}\)

Numerator 5 and denominator 10 share factor 5: \(\frac{5}{10} = \frac{1}{2}\)

Numerator 6 and denominator 3 share factor 3: \(\frac{6}{3} = \frac{2}{1}\)

Step 2: Apply cross-cancellations systematically

\(\frac{2}{3} \times \frac{5}{4} \times \frac{6}{10} = \frac{2 \div 2}{3 \div 3} \times \frac{5 \div 5}{4 \div 2} \times \frac{6 \div 3}{10 \div 5} = \frac{1}{1} \times \frac{1}{2} \times \frac{2}{2}\)

Step 3: Simplify remaining fractions

\(\frac{2}{2} = 1\), so we have \(\frac{1}{1} \times \frac{1}{2} \times 1 = \frac{1}{2}\)

Step 4: Verify result

Without cross-cancellation: \(\frac{2 \times 5 \times 6}{3 \times 4 \times 10} = \frac{60}{120} = \frac{1}{2}\) ✓

\(\frac{2}{3} \times \frac{5}{4} \times \frac{6}{10} = \frac{1}{2}\)
Final answer:

\(\frac{2}{3} \times \frac{5}{4} \times \frac{6}{10} = \frac{1}{2}\)

Applied rules:

• Multiple fraction multiplication: Multiply all numerators and all denominators

• Systematic cross-cancellation: Cancel across all fractions

Detailed Summary: Fraction Multiplication
\(\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\)
Basic Rule
Key definitions:

Fraction: Represents part of a whole, written as \(\frac{\text{numerator}}{\text{denominator}}\)

Numerator: Number of parts being considered (top number)

Denominator: Total number of equal parts (bottom number)

Cross-cancellation: Canceling common factors between any numerator and any denominator before multiplying

Product: Result of multiplication operation

GCD: Greatest Common Divisor - largest number that divides both numbers

Complete methodology:
  1. Identify fractions: Locate all numerators and denominators
  2. Look for cross-cancellations: Find common factors between any numerator and any denominator
  3. Cancel common factors: Divide both numbers by their GCD
  4. Multiply remaining numerators: Multiply all top numbers together
  5. Multiply remaining denominators: Multiply all bottom numbers together
  6. Simplify if needed: Reduce to lowest terms using GCD
Tip 1: Always cross-cancel first to prevent working with large numbers.
Tip 2: Remember: "top × top, bottom × bottom" - always multiply across.
Tip 3: When multiplying by a whole number, put it over 1.
Tip 4: If result is improper fraction, consider converting to mixed number.
Tip 5: Cross-cancellation can happen multiple times in complex problems.
Common errors: Adding numerators and denominators separately, forgetting to cross-cancel, mixing up multiplication and addition rules.
Exam preparation: Practice cross-cancellation, master simplification, understand when to convert to mixed numbers.
Essential formulas:

• Basic multiplication: \(\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\)

• Whole number multiplication: \(n \times \frac{a}{b} = \frac{na}{b}\)

• Cross-cancellation: Cancel common factors diagonally before multiplying

• Simplification: \(\frac{a}{b} = \frac{a \div \text{GCD}(a,b)}{b \div \text{GCD}(a,b)}\)

• Multiple fractions: \(\frac{a}{b} \times \frac{c}{d} \times \frac{e}{f} = \frac{ace}{bdf}\)

Visualization: Cross-Cancellation Effectiveness
Cross-Cancellation Benefits
Comparison of fraction multiplication with and without cross-cancellation:
\(\frac{12}{15} \times \frac{10}{8}\) vs direct multiplication

Analysis: Cross-cancellation reduces computational complexity significantly.

  • Without cross-cancellation: \(\frac{12 \times 10}{15 \times 8} = \frac{120}{120} = 1\)
  • With cross-cancellation: \(\frac{4}{5} \times \frac{5}{4} = \frac{20}{20} = 1\)
  • Cross-cancellation makes multiplication of large numbers much easier

Questions & Answers

Question: Why is cross-cancellation called the "easy way"? How does it make multiplication easier?

Answer: Cross-cancellation is called the "easy way" because it simplifies the multiplication process:

  • It reduces large numbers to smaller ones before multiplying
  • You avoid having to simplify large fractions at the end
  • Smaller numbers are easier to multiply mentally
  • Less chance of arithmetic errors with smaller numbers

Example: Instead of \(\frac{12}{15} \times \frac{10}{8} = \frac{120}{120}\) (which needs simplification), cross-cancellation gives \(\frac{4}{5} \times \frac{5}{4} = \frac{20}{20} = 1\). Both give the same answer, but cross-cancellation makes it much easier!

Question: When should I cross-cancel versus just multiply normally? Is it always better to cross-cancel?

Answer: You should ALWAYS look for cross-cancellation opportunities first. It's beneficial in every situation:

  • If there are common factors, cross-cancel to make multiplication easier
  • If there are no common factors, proceed with normal multiplication
  • Even if only one pair has a common factor, it still helps

Cross-cancellation is never harmful and often helpful. It's like getting a head start on simplification. For example, in \(\frac{7}{9} \times \frac{3}{14}\), you can cancel 7 and 14 (factor of 7) and 3 and 9 (factor of 3), making it much simpler: \(\frac{1}{3} \times \frac{1}{2} = \frac{1}{6}\).

The worst that happens is you realize there are no common factors, and you proceed normally anyway!

Question: I have trouble remembering whether to multiply the top numbers together or the bottom numbers together. Is there a way to remember?

Answer: Here are some helpful memory aids for fraction multiplication:

  • "Top times top, bottom times bottom" - multiply across the same positions
  • Think of it as "numerators together, denominators together"
  • Visual: Draw arrows from numerator to numerator and denominator to denominator

The rule is: \(\frac{\text{numerator}_1}{\text{denominator}_1} \times \frac{\text{numerator}_2}{\text{denominator}_2} = \frac{\text{numerator}_1 \times \text{numerator}_2}{\text{denominator}_1 \times \text{denominator}_2}\)

Remember: Unlike addition/subtraction, you don't need common denominators for multiplication!

Question: How can I check if my fraction multiplication is correct? Sometimes I'm not sure about my answer.

Answer: Here are several methods to verify your fraction multiplication:

Method 1: Reverse calculation - If \(\frac{a}{b} \times \frac{c}{d} = \frac{e}{f}\), then \(\frac{e}{f} \div \frac{c}{d}\) should equal \(\frac{a}{b}\)

Method 2: Decimal conversion - Convert fractions to decimals and multiply to see if results match

Method 3: Estimate - Make sure your answer is reasonable compared to the given values

Method 4: Factor check - Verify that the numerator and denominator of your result have no common factors (already simplified)

Example: For \(\frac{2}{3} \times \frac{3}{4} = \frac{6}{12} = \frac{1}{2}\), check: \(\frac{1}{2} \div \frac{3}{4} = \frac{1}{2} \times \frac{4}{3} = \frac{4}{6} = \frac{2}{3}\) ✓

Question: What happens when I multiply fractions and get an improper fraction? How does that work?

Answer: When multiplying fractions results in an improper fraction (numerator > denominator), the result is perfectly valid:

  • The multiplication process remains the same
  • An improper fraction means the result is larger than one whole
  • You can convert to a mixed number if needed: \(\frac{4}{3} = 1\frac{1}{3}\)

Example: \(\frac{3}{2} \times \frac{4}{3} = \frac{12}{6} = 2\). This means you have 2 whole units, which makes sense because you're multiplying two fractions that are each greater than 1.

Remember: Improper fractions are valid results in fraction multiplication!