Expanded Notation: Writing a number as the sum of each digit multiplied by its place value
Standard Form: The normal way we write numbers (e.g., 3,456)
Place Value: The value of a digit based on its position in the number
Digit: Any of the numerals from 0 to 9
Product: The result of multiplication (digit × place value)
| Place | Value | Example |
|---|---|---|
| Thousands | 1,000 | 3 × 1,000 = 3,000 |
| Hundreds | 100 | 4 × 100 = 400 |
| Tens | 10 | 5 × 10 = 50 |
| Ones | 1 | 6 × 1 = 6 |
Number: 4,567
Task: Write in expanded notation
- Identify each digit and its place value
- Multiply each digit by its place value
- Write all products as a sum
- Verify the sum equals the original number
4 is in the thousands place (value: 1,000)
5 is in the hundreds place (value: 100)
6 is in the tens place (value: 10)
7 is in the ones place (value: 1)
4 × 1,000 = 4,000
5 × 100 = 500
6 × 10 = 60
7 × 1 = 7
4,567 = 4,000 + 500 + 60 + 7
4,000 + 500 + 60 + 7 = 4,567 ✓
4,567 = 4,000 + 500 + 60 + 7
• Place Value Multiplication: Each digit × its place value
• Summation: Add all products to get expanded notation
• Verification: Check that the sum equals the original number
Number: 3,040
Task: Write in expanded notation
3 is in the thousands place (value: 1,000)
0 is in the hundreds place (value: 100)
4 is in the tens place (value: 10)
0 is in the ones place (value: 1)
3 × 1,000 = 3,000
0 × 100 = 0
4 × 10 = 40
0 × 1 = 0
3,040 = 3,000 + 0 + 40 + 0
Or simplified: 3,040 = 3,000 + 40
3,000 + 0 + 40 + 0 = 3,040 ✓
3,040 = 3,000 + 40
• Zero Values: Any digit 0 multiplied by its place value equals 0
• Placeholder Function: Zeros maintain position even when value is 0
• Simplification: Terms that equal 0 can be omitted from the sum
Expanded notation: 6,000 + 300 + 50 + 2
Task: Find the standard form
6,000 represents 6 in the thousands place
300 represents 3 in the hundreds place
50 represents 5 in the tens place
2 represents 2 in the ones place
Thousands: 6
Hundreds: 3
Tens: 5
Ones: 2
Number: 6,352
6,352 = 6,000 + 300 + 50 + 2 ✓
The number is 6,352
• Reverse Process: Identify the place value each part represents
• Place Value Recognition: Match each term to its place value position
• Verification: Convert back to expanded form to check
Number: 25,678
Task: Write in expanded notation
2 is in the ten thousands place (value: 10,000)
5 is in the thousands place (value: 1,000)
6 is in the hundreds place (value: 100)
7 is in the tens place (value: 10)
8 is in the ones place (value: 1)
2 × 10,000 = 20,000
5 × 1,000 = 5,000
6 × 100 = 600
7 × 10 = 70
8 × 1 = 8
25,678 = 20,000 + 5,000 + 600 + 70 + 8
20,000 + 5,000 + 600 + 70 + 8 = 25,678 ✓
25,678 = 20,000 + 5,000 + 600 + 70 + 8
• Large Numbers: Continue the place value pattern (ten thousands, hundred thousands, etc.)
• Sequential Processing: Work from highest to lowest place value
• Verification: Always check that the sum equals the original number
Real-world application: Student population
Number: 12,345
1 is in the ten thousands place (value: 10,000)
2 is in the thousands place (value: 1,000)
3 is in the hundreds place (value: 100)
4 is in the tens place (value: 10)
5 is in the ones place (value: 1)
1 × 10,000 = 10,000
2 × 1,000 = 2,000
3 × 100 = 300
4 × 10 = 40
5 × 1 = 5
12,345 = 10,000 + 2,000 + 300 + 40 + 5
10,000 represents 10,000 students (the ten thousands component)
2,000 represents 2,000 students (the thousands component)
300 represents 300 students (the hundreds component)
40 represents 40 students (the tens component)
5 represents 5 students (the ones component)
12,345 = 10,000 + 2,000 + 300 + 40 + 5
This means the district has 10,000 + 2,000 + 300 + 40 + 5 = 12,345 total students
• Contextual Understanding: Apply mathematical concepts to real-world situations
• Place Value Multiplication: Each digit × its place value
• Real-World Relevance: Connect abstract concepts to practical applications
Expanded Notation: Writing a number as the sum of each digit multiplied by its place value
Standard Form: The normal way we write numbers (e.g., 3,456)
Place Value: The value of a digit based on its position in the number
Digit: Any of the numerals from 0 to 9
- Identify digits: Look at each digit in the number
- Determine place values: Identify the place value for each digit
- Multiply: Multiply each digit by its place value
- Add: Write all products as a sum
- Verify: Check that the sum equals the original number
• Expanded Notation: abcde = (a × 10,000) + (b × 1,000) + (c × 100) + (d × 10) + (e × 1)
• Place Values: ..., Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones
• Verification: Sum of expanded parts = Original number
Number 45,678 breakdown:
(4 × 10,000) + (5 × 1,000) + (6 × 100) + (7 × 10) + (8 × 1)
= 40,000 + 5,000 + 600 + 70 + 8