Divisibility Rules: 10 Solved Exercises with Solutions

Master divisibility rules: quick division tests, prime factorization, and number theory through these 10 detailed exercises.

Divisibility Rules Exercises 1 to 3
1 Divisibility by 2
Exercise 1
Is 3,456 divisible by 2? Explain your reasoning using the divisibility rule for 2.
Definition:

Divisibility rule for 2: A number is divisible by 2 if its last digit is even (0, 2, 4, 6, or 8).

Divisibility checking method:
  1. Identify the last digit of the number
  2. Check if the last digit is even (0, 2, 4, 6, 8)
  3. If even, the number is divisible by 2
  4. If odd, the number is not divisible by 2
Number
3,456
Last Digit
6
Result
Divisible
Step 1: Identify the last digit

The number is 3,456

The last digit is 6

Step 2: Check if the last digit is even

Even digits: 0, 2, 4, 6, 8

Since 6 is in this list, it is even

Step 3: Apply the rule

Since the last digit is even, the number is divisible by 2

Step 4: Verify with division

3,456 ÷ 2 = 1,728

Since there's no remainder, the number is indeed divisible by 2

3,456 is divisible by 2
Final answer:

Yes, 3,456 is divisible by 2 because its last digit (6) is even.

Applied rules:

Rule for 2: Last digit must be even

Even digits: 0, 2, 4, 6, 8

Odd digits: 1, 3, 5, 7, 9

2 Divisibility by 3
Exercise 2
Is 4,827 divisible by 3? Use the divisibility rule for 3 to determine your answer.
Definition:

Divisibility rule for 3: A number is divisible by 3 if the sum of its digits is divisible by 3.

Number
4,827
Digit Sum
4+8+2+7=21
Result
Divisible
Step 1: Add all digits

Digits of 4,827: 4, 8, 2, 7

Sum = 4 + 8 + 2 + 7 = 21

Step 2: Check if sum is divisible by 3

Is 21 divisible by 3?

21 ÷ 3 = 7 with no remainder

Step 3: Apply the rule

Since 21 is divisible by 3, the original number 4,827 is also divisible by 3

Step 4: Verify with division

4,827 ÷ 3 = 1,609

Since there's no remainder, the number is divisible by 3

4,827 is divisible by 3
Final answer:

Yes, 4,827 is divisible by 3 because the sum of its digits (21) is divisible by 3.

Applied rules:

Rule for 3: Sum of digits must be divisible by 3

Digit addition: Add each digit individually

Verification: Division confirms the rule

3 Divisibility by 5
Exercise 3
Which of these numbers are divisible by 5: 1,230, 4,567, 8,905, 3,421? Explain your reasoning.
Definition:

Divisibility rule for 5: A number is divisible by 5 if its last digit is 0 or 5.

Numbers
1230, 4567, 8905, 3421
Last Digits
0, 7, 5, 1
Divisible?
Yes, No, Yes, No
Step 1: Check each number's last digit

1,230: Last digit is 0

4,567: Last digit is 7

8,905: Last digit is 5

3,421: Last digit is 1

Step 2: Apply the rule for each number

Rule: Last digit must be 0 or 5

1,230: 0 → Divisible by 5

4,567: 7 → Not divisible by 5

8,905: 5 → Divisible by 5

3,421: 1 → Not divisible by 5

Step 3: List the divisible numbers

Numbers divisible by 5: 1,230 and 8,905

Step 4: Verify with division

1,230 ÷ 5 = 246 ✓

8,905 ÷ 5 = 1,781 ✓

Numbers divisible by 5: 1,230 and 8,905
Final answer:

Numbers divisible by 5 are 1,230 and 8,905 because their last digits are 0 and 5 respectively.

Applied rules:

Rule for 5: Last digit must be 0 or 5

Binary check: Only two acceptable endings

Quick identification: Just examine the last digit

Divisibility Rules Exercises 4 to 5
4 Divisibility by 9
Exercise 4
Is 7,389 divisible by 9? Use the divisibility rule for 9 to determine your answer.
Definition:

Divisibility rule for 9: A number is divisible by 9 if the sum of its digits is divisible by 9.

Number
7,389
Digit Sum
7+3+8+9=27
Result
Divisible
Step 1: Add all digits

Digits of 7,389: 7, 3, 8, 9

Sum = 7 + 3 + 8 + 9 = 27

Step 2: Check if sum is divisible by 9

Is 27 divisible by 9?

27 ÷ 9 = 3 with no remainder

Step 3: Apply the rule

Since 27 is divisible by 9, the original number 7,389 is also divisible by 9

Step 4: Verify with division

7,389 ÷ 9 = 821

Since there's no remainder, the number is divisible by 9

7,389 is divisible by 9
Final answer:

Yes, 7,389 is divisible by 9 because the sum of its digits (27) is divisible by 9.

Applied rules:

Rule for 9: Sum of digits must be divisible by 9

Similar to 3: Same digit sum principle

Verification: Division confirms the rule

5 Divisibility by 6
Exercise 5
Is 4,632 divisible by 6? Explain your reasoning using the divisibility rule for 6.
Definition:

Divisibility rule for 6: A number is divisible by 6 if it is divisible by both 2 and 3.

Number
4,632
Test 2
Last digit: 2 (even)
Test 3
Sum: 4+6+3+2=15
Result
Divisible
Step 1: Check divisibility by 2

Last digit of 4,632 is 2

Since 2 is even, the number is divisible by 2

Step 2: Check divisibility by 3

Sum of digits: 4 + 6 + 3 + 2 = 15

Is 15 divisible by 3? 15 ÷ 3 = 5 with no remainder

Yes, 15 is divisible by 3

Step 3: Apply the rule for 6

Since 4,632 is divisible by both 2 and 3, it is divisible by 6

Step 4: Verify with division

4,632 ÷ 6 = 772

Since there's no remainder, the number is divisible by 6

4,632 is divisible by 6
Final answer:

Yes, 4,632 is divisible by 6 because it is divisible by both 2 (last digit is even) and 3 (digit sum is 15, which is divisible by 3).

Applied rules:

Rule for 6: Must satisfy both rules for 2 and 3

Compound rule: Both conditions must be true

Verification: Check both conditions independently

Divisibility Rules Laws and Methods
Divisible by n ⟺ Remainder = 0
Divisibility Definition
Rule 2
Last digit even
Ends in 0,2,4,6,8
Rule 3
Digit sum ÷ 3
Sum divisible by 3
Rule 5
Last digit 0 or 5
Ends in 0 or 5

Divisibility Rules Reference

Rule for 2
Last digit even
Rule for 3
Digit sum divisible by 3
Rule for 4
Last two digits divisible by 4
Rule for 5
Last digit 0 or 5
1
Identify Number
Look at digits
2
Apply Rule
Use correct test
3
Check Result
Divisible or not
Test 2
Even digit
Test 3
Sum ÷ 3
Test 5
0 or 5
Rule 6
Both 2 and 3
Rule 9
Digit sum ÷ 9
Rule 10
Ends in 0
Rule 12
Both 3 and 4
Divisibility Laws, Methods, and Definitions
a ÷ b = q \text{ with remainder } r
Division with Remainder
Key definitions:

Divisibility: A number a is divisible by another number b if a ÷ b results in a whole number with no remainder.

Factor: A number that divides another number evenly without leaving a remainder.

Multiple: The product of a number and an integer (e.g., multiples of 3: 3, 6, 9, 12, 15...).

Prime number: A number greater than 1 that has only two factors: 1 and itself.

Composite number: A number greater than 1 that has more than two factors.

Remainder: The amount left over when one number does not divide evenly into another.

Divisibility testing methodology:
  1. Identify the divisor: Determine which number you're testing divisibility by
  2. Select the rule: Choose the appropriate divisibility rule for that number
  3. Apply the rule: Follow the specific steps of the chosen rule
  4. Calculate: Perform the necessary arithmetic
  5. Check result: Determine if the condition is met
  6. Verify: Optionally divide to confirm the result
Tip 1: Remember the rule for 6: it must be divisible by both 2 and 3.
Tip 2: For 4, only check the last two digits, not the entire number.
Tip 3: The rules for 3 and 9 are similar: sum the digits and check divisibility.
Tip 4: Practice with different numbers to build fluency with the rules.
Common errors: Forgetting to check all conditions for compound rules, misidentifying last digits, miscalculating digit sums.
Key insight: Divisibility rules are shortcuts that save time compared to actual division.
Essential divisibility rules to know:

Rule for 2: Last digit is even (0, 2, 4, 6, 8)

Rule for 3: Sum of digits is divisible by 3

Rule for 4: Last two digits form a number divisible by 4

Rule for 5: Last digit is 0 or 5

Rule for 6: Divisible by both 2 and 3

Rule for 9: Sum of digits is divisible by 9

Rule for 10: Last digit is 0

Additional Exercises 6-10
6 Divisibility by 4
Exercise 6
Is 5,724 divisible by 4? Use the divisibility rule for 4 to determine your answer.
Solution:

Rule for 4: Check if the last two digits form a number divisible by 4

Last two digits: 24

Is 24 divisible by 4? 24 ÷ 4 = 6 ✓

Yes, 5,724 is divisible by 4

7 Divisibility by 10
Exercise 7
Which numbers are divisible by 10: 3,450, 7,892, 10,005, 5,600? Explain your reasoning.
Solution:

Rule for 10: Last digit must be 0

3,450: Last digit is 0 → Divisible by 10

7,892: Last digit is 2 → Not divisible by 10

10,005: Last digit is 5 → Not divisible by 10

5,600: Last digit is 0 → Divisible by 10

Numbers divisible by 10: 3,450 and 5,600

8 Divisibility by 12
Exercise 8
Is 4,896 divisible by 12? Use the divisibility rule for 12 to determine your answer.
Solution:

Rule for 12: Must be divisible by both 3 and 4

Check for 3: 4+8+9+6 = 27, 27÷3 = 9 ✓

Check for 4: Last two digits are 96, 96÷4 = 24 ✓

Since divisible by both 3 and 4, 4,896 is divisible by 12

9 Multiple Divisors
Exercise 9
For the number 2,520, list all divisors from 2 to 10 that it is divisible by.
Solution:

Number: 2,520

2: Last digit is 0 (even) ✓

3: 2+5+2+0 = 9, 9÷3 = 3 ✓

4: Last two digits 20, 20÷4 = 5 ✓

5: Last digit is 0 ✓

6: Divisible by 2 and 3 ✓

7: 2520÷7 = 360 ✓

8: Last three digits 520, 520÷8 = 65 ✓

9: 2+5+2+0 = 9, 9÷9 = 1 ✓

10: Last digit is 0 ✓

Divisible by: 2, 3, 4, 5, 6, 7, 8, 9, 10

10 Prime Factorization
Exercise 10
Use divisibility rules to help find the prime factorization of 84.
Solution:

84: Divisible by 2 (even), so 84 = 2 × 42

42: Divisible by 2 (even), so 42 = 2 × 21

21: Divisible by 3 (2+1=3), so 21 = 3 × 7

7: Prime number

Prime factorization: 84 = 2² × 3 × 7

Questions & Answers

Question: Why do we need divisibility rules? Can't I just divide the number to see if it goes in evenly?

Answer: Great question! Divisibility rules are valuable shortcuts that save time and mental energy:

  • Speed: Checking the last digit is faster than long division
  • Mental math: You can quickly determine divisibility without paper
  • Large numbers: Much easier to check divisibility of large numbers
  • Problem solving: Useful for factoring, simplifying fractions, finding multiples

For example, to check if 1,234,567 is divisible by 3, just add: 1+2+3+4+5+6+7 = 28. Since 28 isn't divisible by 3, neither is the large number!

Question: My child is getting confused with the divisibility rules. How can I help them remember them better?

Answer: Here are memory aids for divisibility rules:

  • Rule 2: "Even Steven" - even numbers are divisible by 2
  • Rule 3: "Add me up" - add digits and see if sum is divisible by 3
  • Rule 5: "Five or Zero" - ends in 5 or 0
  • Rule 6: "Both Two and Three" - must satisfy both rules
  • Rule 9: "Add to Nine" - like rule 3 but for 9
  • Rule 10: "Zero Hero" - must end in 0

Practice with different numbers regularly and use flashcards to reinforce the rules!

Question: What if a number is divisible by more than one number? Like 12 - is it divisible by 2, 3, 4, and 6?

Answer: Yes, absolutely! Many numbers are divisible by multiple numbers:

  • 12 is divisible by: 1, 2, 3, 4, 6, 12
  • These are called factors of 12
  • Every number is divisible by 1 and itself
  • Some numbers like 12 have many factors (called composite numbers)
  • Prime numbers only have 2 factors: 1 and themselves

For 12: 12÷1=12, 12÷2=6, 12÷3=4, 12÷4=3, 12÷6=2, 12÷12=1

So yes, 12 satisfies the divisibility rules for 2, 3, 4, and 6!

Detailed Summary: Divisibility Rules
Key Concepts and Definitions:

Divisibility: A number is divisible by another number if the division results in a whole number with no remainder.

Divisibility Rule: A shortcut method to determine if one number divides another evenly without performing the actual division.

Factor: A number that divides another number evenly without leaving a remainder.

Multiple: The result of multiplying a number by an integer (e.g., multiples of 4: 4, 8, 12, 16...).

Prime Number: A number greater than 1 that has exactly two factors: 1 and itself.

Composite Number: A number greater than 1 that has more than two factors.

Remainder: The amount left over when one number does not divide evenly into another.

Step-by-Step Divisibility Testing Method:
  1. Identify the divisor: Determine which number you're testing divisibility by (2, 3, 4, 5, 6, etc.).
  2. Select the appropriate rule: Choose the specific divisibility rule for that number.
  3. Apply the rule: Follow the exact steps of the chosen rule methodically.
  4. Perform calculations: Carry out any necessary arithmetic (adding digits, checking last digits).
  5. Check conditions: Determine if the conditions of the rule are met.
  6. State the result: Clearly indicate whether the number is divisible or not.
  7. Verify if needed: Optionally perform the actual division to confirm your result.
Tips for Success: Practice each rule individually before combining them. Use the rules as mental shortcuts for quick checks.
Common Pitfalls: Forgetting to check all conditions for compound rules (like 6), misidentifying last digits, miscalculating digit sums.
Memorization Aid: Remember "SPEED" - Sum (for 3/9), Product (for 2), End digit (for 5), Even (for 2), Divisible by both (for 6).
Key Rule: Divisibility rules are shortcuts that save time compared to performing actual division.
Analysis Tip: Compound rules require satisfying multiple conditions simultaneously (e.g., 6 requires both 2 and 3).
Essential Divisibility Rules:

Rule for 2: A number is divisible by 2 if its last digit is even (0, 2, 4, 6, 8)

Rule for 3: A number is divisible by 3 if the sum of its digits is divisible by 3

Rule for 4: A number is divisible by 4 if the last two digits form a number divisible by 4

Rule for 5: A number is divisible by 5 if its last digit is 0 or 5

Rule for 6: A number is divisible by 6 if it is divisible by both 2 and 3

Rule for 9: A number is divisible by 9 if the sum of its digits is divisible by 9

Rule for 10: A number is divisible by 10 if its last digit is 0