Parallel Sides (Bases): The two sides of a trapezoid that are parallel to each other. These are called the top base and bottom base.
- Identify the two parallel sides (bases)
- Identify the height (perpendicular distance between bases)
- Apply the area formula: A = ½(b₁ + b₂)h
- Substitute the values
- Calculate the result
- Include the units (cm²)
b₁ = 10 cm, b₂ = 14 cm, h = 6 cm
Area = ½ × (sum of parallel sides) × height
Area = ½ × (b₁ + b₂) × h
Area = ½ × (10 + 14) × 6
Area = ½ × 24 × 6
Area = 12 × 6 = 72 cm²
Check: (10 + 14) ÷ 2 = 12, then 12 × 6 = 72 ✓
The area of the trapezoid is 72 cm².
• Trapezoid Area Formula: A = ½(b₁ + b₂)h
• Parallel Sides: Must identify the two parallel sides
• Perpendicular Height: Height must be perpendicular to bases
Rearranging the Area Formula: When area and some dimensions are known, rearrange A = ½(b₁ + b₂)h to find the missing dimension.
A = ½(b₁ + b₂)h
2A = (b₁ + b₂)h
2A/h = b₁ + b₂
b₂ = (2A/h) - b₁
b₂ = (2 × 120)/8 - 15
b₂ = 240/8 - 15
b₂ = 30 - 15
b₂ = 15 cm
Area = ½(15 + 15) × 8 = ½ × 30 × 8 = 15 × 8 = 120 cm² ✓
The length of the other base is 15 cm.
• Formula Rearrangement: Isolate the unknown variable
• Algebraic Manipulation: Multiply both sides by 2, then divide by height
• Verification: Substitute back to check the answer
Rectangle as Trapezoid: A rectangle is a special case of a trapezoid where both pairs of opposite sides are parallel. Both bases are equal in length.
Rectangle is a trapezoid where both bases are equal: b₁ = b₂ = 12 cm
Height = width = 8 cm
Area = ½(b₁ + b₂)h
Area = ½(12 + 12) × 8
Area = ½(24) × 8
Area = 12 × 8
Area = 96 cm²
Rectangle Area = length × width = 12 × 8 = 96 cm² ✓
The area of the rectangle is 96 cm². A rectangle is a special trapezoid where both bases are equal.
• Rectangle Property: Special case of trapezoid
• Area Formula: A = ½(b₁ + b₂)h (becomes A = ½(2b)h = bh)
• Equality of Bases: In rectangle, both parallel sides are equal
Trapezoid: A quadrilateral with exactly one pair of parallel sides. The parallel sides are called bases.
Bases: The two parallel sides of a trapezoid. Usually denoted as b₁ and b₂.
Legs: The two non-parallel sides of a trapezoid.
Height: The perpendicular distance between the two parallel bases.
Isosceles Trapezoid: A trapezoid with equal legs and equal base angles.
Midsegment: The line segment connecting the midpoints of the legs. Its length equals the average of the bases.
- Identify the Trapezoid: Ensure exactly one pair of sides is parallel
- Determine Bases and Height: Identify the two parallel sides and perpendicular height
- Apply the Formula: A = ½(b₁ + b₂)h
- Substitute Values: Plug in the known measurements
- Calculate: Perform the addition, multiplication, and division
- Check Units: Ensure answer is in square units
• Standard Trapezoid: A = ½(b₁ + b₂)h
• Base: b₂ = (2A/h) - b₁
• Height: h = 2A/(b₁ + b₂)
• Midsegment: m = (b₁ + b₂)/2
• Using Midsegment: A = m × h
• Rectangle: A = length × width
Isosceles Trapezoid: A trapezoid with equal legs and equal base angles. The height can be found using the Pythagorean theorem.
When we draw the height from both top vertices, we create two right triangles and a rectangle
The base of each right triangle = (16 - 10) ÷ 2 = 3 cm
In the right triangle: leg² = height² + base²
5² = h² + 3²
25 = h² + 9
h² = 16
h = 4 cm
Area = ½(b₁ + b₂)h
Area = ½(16 + 10) × 4
Area = ½(26) × 4 = 13 × 4 = 52 cm²
Check: 3² + 4² = 9 + 16 = 25 = 5² ✓
Area check: ½(26) × 4 = 52 ✓
The height of the trapezoid is 4 cm and the area is 52 cm².
• Isosceles Trapezoid Property: Equal legs create symmetric triangles
• Pythagorean Theorem: Used to find height from leg length
• Trapezoid Area Formula: A = ½(b₁ + b₂)h
Composite Figure: A shape made up of two or more simple geometric figures. To find the area, calculate the area of each part and combine as needed.
Rectangle Area = length × width
Rectangle Area = 20 × 12 = 240 m²
Trapezoid Area = ½(b₁ + b₂)h
Trapezoid Area = ½(8 + 4) × 3 = ½(12) × 3 = 6 × 3 = 18 m²
Remaining Area = Rectangle Area - Trapezoid Area
Remaining Area = 240 - 18 = 222 m²
Check: 240 - 18 = 222 ✓
The remaining area should be less than the original area ✓
The remaining area of the garden is 222 m².
• Composite Area: Total Area = Sum of parts or Difference of parts
• Rectangle Area: A = length × width
• Trapezoid Area: A = ½(b₁ + b₂)h
Trapezoid: A quadrilateral with exactly one pair of parallel sides. The parallel sides are called bases.
Area: The measure of the surface enclosed by a shape, expressed in square units (cm², m², etc.).
Bases: The two parallel sides of a trapezoid, usually denoted as b₁ (top base) and b₂ (bottom base).
Height: The perpendicular distance between the two parallel bases.
Legs: The two non-parallel sides of a trapezoid.
Isosceles Trapezoid: A trapezoid with equal legs and equal base angles.
Midsegment: The segment connecting the midpoints of the legs; its length equals the average of the bases.
- Identify the Trapezoid: Confirm it has exactly one pair of parallel sides
- Find Bases and Height: Ensure height is perpendicular to the bases
- Select Appropriate Formula: Use A = ½(b₁ + b₂)h
- Substitute Values: Replace variables with given measurements
- Calculate Carefully: Perform addition, multiplication, and division in correct order
- Verify Solution: Check calculations and ensure answer is reasonable
• Standard Trapezoid: A = ½(b₁ + b₂)h
• Base 2: b₂ = (2A/h) - b₁
• Base 1: b₁ = (2A/h) - b₂
• Height: h = 2A/(b₁ + b₂)
• Midsegment: m = (b₁ + b₂)/2
• Using Midsegment: A = m × h
• Rectangle: A = length × width
Fixed area of 60 m² with varying base sums and heights
Showing the inverse relationship
Analysis: The chart shows how base sums and height are inversely related for a fixed area.
- When base sum doubles, height halves to maintain the same area
- Product of (base sum) and height is constant for fixed area
- Area remains the same regardless of base-height combination
- The relationship follows (b₁+b₂)h = 2A (constant)