Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.
- Identify the y-intercept (b) from the graph
- Calculate the slope (m) from the graph
- Substitute m and b into y = mx + b
The line crosses the y-axis at (0, 3)
Therefore, b = 3
From the graph, the slope is 2 (rise of 2 for every run of 1)
Therefore, m = 2
Substitute m = 2 and b = 3 into y = mx + b
y = 2x + 3
Check point (1, 5): y = 2(1) + 3 = 5 ✓
Check y-intercept (0, 3): y = 2(0) + 3 = 3 ✓
The equation of the line is y = 2x + 3.
• Slope-intercept form: y = mx + b
• Y-intercept: Point where x = 0
• Slope: Rise over run
Point-slope form: y - y₁ = m(x - x₁), where (x₁, y₁) is a point and m is the slope.
Use the slope formula: m = (y₂ - y₁)/(x₂ - x₁)
m = (8 - 4)/(3 - 1) = 4/2 = 2
Using point (1, 4) and slope m = 2
y - 4 = 2(x - 1)
y - 4 = 2x - 2
y = 2x - 2 + 4
y = 2x + 2
Check point (1, 4): y = 2(1) + 2 = 4 ✓
Check point (3, 8): y = 2(3) + 2 = 8 ✓
The equation of the line is y = 2x + 2.
• Slope formula: m = (y₂ - y₁)/(x₂ - x₁)
• Point-slope form: y - y₁ = m(x - x₁)
• Conversion: Point-slope to slope-intercept form
Intercept form: When given both intercepts, use them to find slope and write the equation.
X-intercept: (4, 0) - where line crosses x-axis
Y-intercept: (0, 6) - where line crosses y-axis
Use the slope formula with the two intercepts:
m = (6 - 0)/(0 - 4) = 6/(-4) = -3/2
Since y-intercept is (0, 6), b = 6
Since slope m = -3/2
y = (-3/2)x + 6
y = -3/2x + 6
Check x-intercept (4, 0): y = -3/2(4) + 6 = -6 + 6 = 0 ✓
Check y-intercept (0, 6): y = -3/2(0) + 6 = 6 ✓
The equation of the line is y = -3/2x + 6.
• Y-intercept: Directly gives b value in y = mx + b
• Slope from intercepts: Use both intercepts as two points
• Negative slope: Line falls from left to right
Linear equation: An equation whose graph is a straight line. The highest power of the variable is 1.
Slope (m): The measure of steepness of a line, calculated as rise over run.
Y-intercept (b): The point where the line crosses the y-axis (when x = 0).
X-intercept: The point where the line crosses the x-axis (when y = 0).
Ordered pair: A pair of numbers (x, y) that represents a point on the coordinate plane.
Graph interpretation: Reading information from a visual representation of a linear relationship.
- Observe the graph: Identify key features like intercepts and direction
- Find the slope: Calculate rise over run or identify from the graph
- Find the y-intercept: Locate where the line crosses the y-axis
- Substitute values: Put slope and y-intercept into y = mx + b
- Verify: Check that the equation fits the graph
• Slope-intercept form: y = mx + b
• Y-intercept: value of y when x = 0
• Slope: rise over run (change in y divided by change in x)
• Positive slope: line rises left to right
• Negative slope: line falls left to right
• Zero slope: horizontal line
Standard form: Ax + By = C, where A, B, and C are integers, and A is typically positive.
From the graph, y-intercept is -4 and slope is 3
y = 3x - 4
Start with: y = 3x - 4
Subtract 3x from both sides: -3x + y = -4
Multiply by -1 to make A positive: 3x - y = 4
A = 3, B = -1, C = 4 (all integers)
A is positive ✓
Using point (2, 2): 3(2) - 2 = 6 - 2 = 4 ✓
The equation in standard form is 3x - y = 4.
• Standard form: Ax + By = C where A, B, C are integers
• Positive A: Standard form typically has A > 0
• Algebraic manipulation: Rearrange terms to achieve standard form
Real-world applications: Linear equations model practical situations with constant rates of change.
m = (170 - 50)/(4 - 0) = 120/4 = 30
This means $30 per hour
Point (0, 50) shows that when x = 0, y = 50
Therefore, b = 50
Substituting m = 30 and b = 50:
y = 30x + 50
When x = 0 (no hours worked), y = 50
This represents a base payment or signing bonus of $50
Check (4, 170): y = 30(4) + 50 = 120 + 50 = 170 ✓
The equation is y = 30x + 50, where the y-intercept of 50 represents a $50 base payment before any hours are worked.
• Real-world interpretation: Y-intercept often represents initial value
• Slope interpretation: Rate of change in context
• Modeling: Linear equations represent real-world relationships
Writing equations from graphs: The process of analyzing a visual representation of a linear relationship to determine its algebraic form.
Slope (m): The steepness of a line, calculated as the ratio of vertical change to horizontal change between any two points.
Y-intercept (b): The point where the line crosses the y-axis, occurring when x = 0.
Linear function: A function that produces a straight line when graphed, with a constant rate of change.
Graph interpretation: Reading quantitative information from a visual representation to extract mathematical relationships.
Coordinate identification: Locating and reading ordered pairs (x, y) from a graph accurately.
- Survey the graph: Observe the general shape, direction, and key points
- Identify y-intercept: Locate where the line crosses the y-axis
- Calculate slope: Determine rise over run using any two convenient points
- Substitute values: Plug slope and y-intercept into y = mx + b
- Verify accuracy: Test the equation with additional points from the graph
- Convert if needed: Change to required form (standard, point-slope, etc.)
• Slope-intercept form: y = mx + b
• Slope calculation: m = (y₂ - y₁)/(x₂ - x₁)
• Y-intercept: value of y when x = 0
• Positive slope: line rises left to right
• Negative slope: line falls left to right
• Standard form: Ax + By = C (A, B, C are integers)
Writing Equations from Graphs Guide
Find where line crosses y-axis
This is the b value
Point: (0, b)
m = rise/run
Choose two clear points
m = (y₂ - y₁)/(x₂ - x₁)
y = mx + b
Substitute slope and y-intercept
Verify with graph points
Test multiple points
Check direction of line
Confirm slope and intercept