Percent Word Problem: A mathematical problem presented in a real-world context that requires calculating percentages of quantities.
- Identify the total quantity (whole)
- Identify the percentage
- Convert percentage to decimal (divide by 100)
- Multiply total by decimal to find the part
- Verify the answer makes sense in context
Total students = 40
Percentage of girls = 60%
60% = 60 ÷ 100 = 0.60
Number of girls = Total × Decimal
Number of girls = 40 × 0.60 = 24
Number of boys = Total - Girls
Number of boys = 40 - 24 = 16
There are 24 girls and 16 boys in the class.
• Decimal Conversion: Percent ÷ 100 = Decimal
• Multiplication Rule: Part = Whole × Decimal
• Complementary Rule: Part 2 = Whole - Part 1
When solving percent word problems, always identify the whole (total) and the percentage. The part is found by multiplying the whole by the decimal equivalent of the percentage.
Sequential Percent Changes: When multiple percentage changes are applied one after another, each change is applied to the current value, not the original value.
After 25% discount, customer pays 75% of original price
First sale price = $120 × (1 - 0.25) = $120 × 0.75 = $90
Additional 10% off the current sale price
Final price = $90 × (1 - 0.10) = $90 × 0.90 = $81
Total discount = $120 - $81 = $39
Total discount percentage = ($39 ÷ $120) × 100% = 32.5%
The sale price after the first discount is $90. The final price after both discounts is $81.
• Sequential Application: Apply each percentage change to the current value
• Decimal Conversion: For discounts, multiply by (1 - decimal)
• Compound Effect: Multiple discounts don't add up linearly
Compound Growth: When a quantity increases by a percentage each period, and subsequent increases are calculated on the new amount rather than the original amount.
Population after 12% increase = 8,000 × (1 + 0.12)
Population after 12% increase = 8,000 × 1.12 = 8,960
Population after 8% increase = 8,960 × (1 + 0.08)
Population after 8% increase = 8,960 × 1.08 = 9,676.8
Overall increase = (Final - Original) ÷ Original × 100%
Overall increase = (9,676.8 - 8,000) ÷ 8,000 × 100% = 20.96%
The population will be approximately 9,677 next year. The overall percentage increase from last year is 20.96%.
• Sequential Increases: Apply each percentage increase to the current value
• Compound Effect: Multiple increases compound rather than add
• Overall Calculation: Use original and final values for total percentage
When dealing with multiple percentage changes, each change is applied to the result of the previous change, not the original amount. This creates a compounding effect.
Percent: A ratio or fraction expressed as a part of 100. The symbol % means "per hundred."
Word Problem: A mathematical problem presented in a real-world context using natural language.
Part: The portion of the whole that corresponds to the given percentage.
Whole: The total amount or 100% of the quantity.
- Read Carefully: Understand what the problem is asking
- Identify Components: Determine what is the part, whole, and percent
- Convert Percent: Change percentage to decimal by dividing by 100
- Select Formula: Choose appropriate formula based on what's unknown
- Calculate: Perform the arithmetic operations
- Verify: Check that the answer makes sense in context
• Decimal Conversion: Divide percent by 100 to get decimal
• Multiplication Order: Decimal × Whole = Part
• Sequential Changes: Apply each percentage change to the current value
• Verification: Part ÷ Whole should equal the decimal form of the percent
Sequential Percentages: When one percentage is applied to the result of another percentage, creating a nested calculation.
Coffee preferrers = Total surveyed × Coffee preference percentage
Coffee preferrers = 500 × 0.45 = 225 people
Daily coffee drinkers = Coffee preferrers × Daily drinking percentage
Daily coffee drinkers = 225 × 0.60 = 135 people
Percentage of total = (Daily coffee drinkers ÷ Total surveyed) × 100%
Percentage of total = (135 ÷ 500) × 100% = 27%
135 people drink coffee daily. This represents 27% of the total surveyed.
• Nested Calculation: Apply percentages sequentially to subsets
• Proportionality: Maintain proportional relationships
• Verification: Check that nested percentages make logical sense
Mixture Problem: A problem involving combining substances of different concentrations to achieve a desired concentration.
Salt needed = Total solution × Desired concentration
Salt needed = 200g × 0.15 = 30g of salt
Amount of 20% solution = Salt needed ÷ Concentration of solution
Amount of 20% solution = 30g ÷ 0.20 = 150g of 20% solution
Water needed = Total solution - Solution with salt
Water needed = 200g - 150g = 50g of water
Salt in mixture = 150g × 0.20 = 30g
Concentration = 30g ÷ 200g = 0.15 = 15% ✓
The chemist should use 150 grams of the 20% salt solution and 50 grams of pure water.
• Mixture Formula: Amount of substance = Total × Concentration
• Mass Conservation: Total mass of components equals total mass of mixture
• Concentration Calculation: Final concentration = Total substance ÷ Total mass
Percent Word Problem: A mathematical problem presented in a real-world context that requires calculating percentages of quantities.
Sequential Percent Changes: When multiple percentage changes are applied one after another, each change is applied to the current value.
Mixture Problems: Problems involving combining substances of different concentrations to achieve a desired concentration.
- Read Carefully: Understand the problem context and what's being asked
- Identify Components: Determine the whole, part, and percent in the problem
- Convert Percent: Change percentage to decimal by dividing by 100
- Select Formula: Choose appropriate formula based on what's unknown
- Set Up Equation: Write the mathematical relationship
- Solve: Perform calculations to find the unknown
- Verify: Check that the answer makes sense in context
• Decimal Conversion: Percent ÷ 100 = Decimal equivalent
• Multiplication Rule: Decimal × Whole = Part
• Sequential Changes: Apply each percentage change to the current value
• Verification: Part ÷ Whole should equal the decimal form of the percent
• Mass Conservation: In mixture problems, total mass is conserved